Use photo math it’s a great tool
I am thinking of a rectangle that has the two sides parallel to one another. Set the two functions equal to one another, so
9x-14=7x+4
After a bunch of algebra and math magic, 2x=18 => x=9
So if you just insert 9 into both equations, both will end up with a value of 67, so it ends up looking like a right triangle. Don't do that. Instead, to find the rectangle widths, use 9x-4 (+10 added to intercept) instead, while keeping 7x+4, so that the intercepts match.
LN) 9x-4 = 9(9)-4 = 81-4 = 77
MP) 7(9)+4 = 63+4 = 67
*If you are also looking for the diagonals, use Pythagorean Theorem 77^2+67^2=(hypotenuse)^2*
1. To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...
2. To find the x-intercept, set y = 0 \displaystyle y=0 y=0.
3. To find the y-intercept, set x = 0 \displaystyle x=0 x=0.
It means like what number equals that number.Use multiplication to figure these out.
Example : 9,15. Factors for 9-9,1,3 .Factors for 15-1,15,3,5
Hope this helps !
