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2 years ago

(m) रेखीय फलन (Linear function)

Mathematics

1 answer:

Law Incorporation [45]2 years ago

5 0

Answer:

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Step-by-step explanation:

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Which ordered pair is in the solution set of the system of linear inequalities? y >3/2 x – 1 y <3/2 x – 1 (–5, 2) (2, 2) (

Vikentia [17]

Answer:

No solution

Option 4 is correct

Step-by-step explanation:

Given: The system of inequality

$y>\dfrac{3}{2}x-1$

$y$

We need to choose correct option.

Option 1: (-5,2)

Put x=-5 and y=2

Equation 1 Equation 2

$2>\dfrac{3}{2}(-5)-1$ $2$

$2>-8.5$ $2$

TRUE FALSE

Option 2: (2,2)

Put x=2 and y=2

Equation 1 Equation 2

$2>\dfrac{3}{2}(2)-1$ $2$

$2>2$ $2$

FALSE FALSE

Option 3: (5,2)

Put x=-5 and y=2

Equation 1 Equation 2

$2>\dfrac{3}{2}(5)-1$ $2$

$2>6.5$ $2$

FALSE TRUE

Option 1, 2 and 3 are incorrect because both equation must be true for solution.

Hence, Option 4 is correct no solution.

6 0

2 years ago

Read 2 more answers

Question:-

Reika [66]

${\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \red{ \dfrac{1}{2} + \dfrac{1}{4} = \dfrac{3}{4} }$

Step by step explanation :-

The only thing you have to do is add the numerator to the denominator, in this case you have to add the first ones from the front, which can be these 2+1/4, which would result in 3/4, and this is called the Commutative Property.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \gray{ \dfrac{1}{2} + \dfrac{1}{4} = \dfrac{1}{4} + \dfrac{1}{2} }}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \green{\dfrac{2 + 1}{4} = \dfrac{1 + 2}{4} }}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\bf \blue{\dfrac{3}{4} = \dfrac{3}{4}} }$

Answer :- The answer is 3/4

¿What is commutative property?

It is to change different ways in order of the addends the result would be the same.

Example :-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\bf \blue{\dfrac{a}{b} + \dfrac{c}{d}} = {\dfrac{c}{d} + \dfrac{a}{b}} }$