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denpristay [2]
3 years ago
11

Employees at Happy Burger must place a special toy in at least 30% of the Burger Buddy kid's meals sold per day. The table shows

data from the 5 days the employees tried to meet this goal. Day Number of Special Toys Given Away Total Number of Burger Buddy Kid's Meals Sold Monday 33 120 Tuesday 32 115 Wednesday 40 109 Thursday 37 101 Friday 40 117 On how many days did the employees meet the goal?
Mathematics
1 answer:
irga5000 [103]3 years ago
6 0
On Monday the percentage was approx. 27% so they did not meet the goal
On Tuesday the percentage was approx. 28% <span>so they did not meet the goal
</span>On Wednesday the percentage was approx. 37% so they did meet the goal
On Thursday the percentage was approx. 37% so they did meet the goal
On Friday the percentage was approx. 34% so they did meet the goal

The employees met the goal 3 times within that week :)
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Plz answer for number 12-18 it homework
solniwko [45]

Answer:

i cant really see take a closer picture plz

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
g natasha is in a class of 30 students that selects 4 leaders. How many ways are there to select the 4 leaders so that natasha i
Papessa [141]

Answer:

<h2>3,654 different ways.</h2>

Step-by-step explanation:

If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).

Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.

29C3 = 29!/(29-3)!3!

29C3 = 29!/(26!)!3!

29C3 = 29*28*27*26!/26!3*2

29C3 = 29*28*27/6

29C3 = 3,654 different ways.

This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders

5 0
3 years ago
Here are the scores of students on a history test. 55, 56, 57, 58, 58, 64, 65, 66, 69, 75, 77, 78, 81, 81, 85, 86, 91. Create a
Anarel [89]
The first thing you need to do is get the median of the whole set.

The median is the center so since there are 17 numbers the center is 69 and 69 is Q2

Next we need to find Q1 Q3 and Q4 Also, are whiskers are below.
Whisker minimum = 55
Whisker maximum = 91

Now to find Q1 we have to get the median of the first half of the data.
We need to get the median of the following data set.
55, 56, 57, 58, 58, 64, 65, 66

(58+58) / 2 = 58
Q1 = 58

Now we need to find Q3. To do that we get the median of the second half of the data.
75, 77, 78, 81, 81, 85, 86, 91. 
(81 + 81) / 2 = 81
Q3 = 81

Now we have all our quartiles and whiskers, which are below, it is time to create our box and whisker plot. Note, create a horizontal or vertical number line with appropriate data. Also the box part is from Q1 to Q3 and your whiskers goes from your minimum to your box and from your maximum to your box.

Whisker Minimum = 55
Q1 = 58
Q2 = 69
Q3 = 81
Whisker Maximum = 91

6 0
3 years ago
Does anyone know this answer
VladimirAG [237]

Answer:

60 degrees

Step-by-step explanation:

The two legs are not equivalent pointing to a 30-60-90 triangle which means x=60 degrees

4 0
3 years ago
Read 2 more answers
A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th
Ugo [173]

Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

(8 + 9 + 10 + 13 + 14 + 16 + 17 + 20 + 21)/9 = 14.2

a)

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 1.96 × 2.8/√9

= 14.2 ± 1.96 × 0.933

= 14.2 ± 1.83

The lower end of the confidence interval is 12.37

The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

n represents the number of samples

It becomes

14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

3 0
3 years ago
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