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3 years ago

-7 -[-6] a.42 b.-1 c.-13 d.-42

Mathematics

2 answers:

Leni [432]3 years ago

6 0

Answer:

B. -1

Step-by-step explanation:

-7-[-6]

Double negatives equal a positive so instead of it being -[-6] it would be +6 and -7+6 = -1

Hope this helps!

kati45 [8]3 years ago

4 0

Answer:

Step-by-step explanation:

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Factor: 36x^2-64<br><br><br>thanks!<br>

Marina CMI [18]

Answer:

4(3x+4)(3x-4)

Step-by-step explanation:

4(9x^2-16)

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2 years ago

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If a coin is tossed 5 times, what is the probability that it will land heads each time

Sever21 [200]

1/2 because there are only two sides heads and tails. applies to each time you toss the coin

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3 years ago

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The gallons of water used to take a shower varies directly with the number of minutes in the shower. If a 6 minute shower uses 3

Lapatulllka [165]

Answer:

You use 6 gallons of water per minute.

Explanation:

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3 years ago

Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago

3) This decimal is colored to show<br> 1

MAVERICK [17]

I believe it’s the first one. i’m very sorry if it’s wrong

3 0

3 years ago