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aleksandr82 [10.1K]
3 years ago
15

Which equation defines the graph of y=x^2 after it is shifted vertically 3 units down and horizontally 5 units left? A) y=(x-5)^

2 - 3 B) y= (x+5)^2 - 3 c) y=(x-3)^2 - 5 D) y= (x+3)^2 - 5
Mathematics
2 answers:
AVprozaik [17]3 years ago
6 0

we have

y=x^{2}

This is a vertical parabola open upward

the vertex is equal to the origin (0,0)

The rule of the translation is

(x,y)------> (x-5,y-3)

that means

the translations is 5 units to the left and 3 units down

therefore

the new vertex of the function will be

(0,0)------> (0-5,0-3)

(0,0)------> (-5,-3)

The new equation of the parabola in vertex form is equal to

y=(x+5)^{2}-3

<u>the answer is the option B</u>

y=(x+5)^{2}-3



jeka943 years ago
3 0
The answers is B because you set x+5=0 and x=-5 so that means that the graph needs to be shifted 5 units to the left because 5 is negative and to move 3 units down you just put a -3 at the end of the equation like this y=(x+5)-3
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