Answer:
The number of child tickets is 53
And adult tickets sold out is 93
Step-by-step explanation:
Let the child tickets be x
And the adult tickets be y
x+y = 146 - - - - - - - 1
x= 146-y
5.3x + 9.3y= 1145.80 - - - - - 2
We can substitute x= 146-y in equation 2
5.3(146-y) + 9.3y= 1145.80 - -- 2
773.8 - 5.3y +9.3y = 1145.80
773.8+4y= 1145.80
4y= 1145.80-773.8
4y= 372
y= 372/4
y= 93
We can now substitute y= 93 in equation 1 to find x
x+ 93= 146
x= 146-93
x= 53
Hence
The number of child tickets is 53
And adult tickets sold out is 93
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4
y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b
so the equation is : y = -4x + 2 <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
Answer:
Step-by-step explanation:
Well 12y is the most obvious answer.
Anything that makes 12 is good enough.
4(3y) is another answer
12(y)
1(12y)
6(2y)
2(6y
Answer:
The correct option is 4.
Step-by-step explanation:
The non parallel sides of an isosceles trapezoid are congruent.
The image of an isosceles trapezoid is same as the preimage of isosceles trapezoid if
1. Reflection across a line joining the midpoints of parallel sides.
2. Rotation by 360° about its center.
3. Rotation by 360° about origin.
If we rotate the trapezoid by 180° about its center, then the parallel sides will interchanged.
If we reflect the trapezoid across a diagonal, then the resultant figure will be a parallelogram.
If we reflect across a line joining the midpoints of the nonparallel sides, then the parallel sides will interchanged.
After rotation by 360° about the center, we always get an onto figure.
Therefore option 4 is correct.
Answer:
1 yard
Step-by-step explanation: