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Neko [114]
3 years ago
8

Identify the horizontal asymptote of f(x)=x^2+6x-9 over x-2

Mathematics
1 answer:
lora16 [44]3 years ago
7 0
\bf \cfrac{x^2+6x-9}{x-2}\qquad 
\begin{cases}
x^2\impliedby \textit{has a degree of 2}\\
x^1\impliedby \textit{has a degree of 1}
\end{cases}

if the degree of the expression of the numerator is greater than that of the denominator, the rational expression has no horizontal asymptote.
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Data

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Process

1.- Divide using long division

                                4x³ - 2x² + 3                          

                   2x + 1   8x⁴ + 0x³ - 2x² + 6x - 7

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                                 0   - 4x³ - 2x²

                                      + 4x³ +2x²

                                          0       0   + 6x - 7

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         px² = -2x²  then  p = -2

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jeka57 [31]

Answer:

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Step-by-step explanation:

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