TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = 112°, 112°, 68°.
Answer:
The MAD of {12, 10, 10, 8, 6, 7, 7, 12} is 2.
Step-by-step explanation:
<u><em>Step 1 : Add all the values Up:</em></u>
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<u><em>Step 2 : Divide them by the number of items or numbers:</em></u>
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<u><em>Step 3: Find the absolute deviations:</em></u>
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<u><em>Step 4: Add all the absolute deviations:</em></u>

<u><em>Step 5: Find the mean:</em></u>

Answer:
36. Limit = 2/3.
Step-by-step explanation:
36.
(∛ x- 1) / (√x - 1)
Rationalise the expression:-
Multiply top and bottom by (√x + 1):-
(∛x - 1)(√x + 1) / (√x - 1)(√x + 1)
= x^5/6 + ∛x - √x - 1 / (x - 1)
Applying L'hopital's rule ( differentiating top and bottom of the fraction) we have:
Limit as x ----> 1 of [5/6 x^-1/6 + 1/3 x^(-2/3) - 1/2x^-1/2] / 1
= 5/6(1) + 1/3(1) - 1/2(1) = 2/3 (answer).
Answer:
(2m -3)(2m -5)
Step-by-step explanation:
You can do this several ways. One of my favorites is to graph the expression to find its zeros. They are 3/2 and 5/2, so the factoring can be ...
... 4(x -3/2)(x -5/2) = (2x -3)(2x -5) . . . . . . after eliminating fractions
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You can also look for factors of 4·15 ("ac") that add to give -16 ("b"). Since "b" is negative, both factors will be negative.
... 4·15 = 60 = (-1)(-60) = (-2)(-30) = (-3)(-20) = (-4)(-15) = (-5)(-12) = (-6)(-10)
The pair -6, -10 has a sum of -16, so we can rewrite the expression as ...
... 4m^2 -6m -10m +15 . . . . . . . replace -16m with -6m -10m (order doesn't matter)
and factor pairs of terms
... (4m^2 -6m) -(10m -15) = 2m(2m -3) -5(2m -3) . . . . . there is a common factor between the pairs
... = (2m -5)(2m -3)