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2 years ago

Points U, M, And D are collinear with U between U and D.

Mathematics

1 answer:

zheka24 [161]2 years ago

5 0

The value of x from the given equation is 5/3

<h3>How to determine the value</h3>

Since the three points are collinear to U, they are on a straight line which equals 0

Then we have,

UM + UD = MD

5x+30 + 10x+20 = 3x+80

Collect like terms

5x + 10x + 50 = 3x + 80

15x - 3x = 80 - 50

12x = 30

x = 30/12 = 15/6 = 5/3

Thus, the value of x from the given equation is 5/3

Learn more about collinear points here:

brainly.com/question/18559402

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$\huge\fbox{Answer ☘}$

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2 years ago

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Answer:

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2 years ago

Convert the polar coordinates (-3, -60°) to Cartesian coordinates.

notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

$r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x$

#Using the illustration above, we can express our polar coordinates as:

$-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}$

#Solve simultaneously to solve for x and y:

$(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6$

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