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ch4aika [34]
3 years ago
15

Marin writes the functions m(x) = StartFraction 3 x Over x + 7 EndFraction and n(x) = StartFraction 7 x Over 3 minus x EndFracti

on. Which equation must be true for m(x) and n(x) to be inverse functions? StartStartFraction 3 (StartFraction 3 x Over x + 7 EndFraction) OverOver (StartFraction 3 x Over x + 7 EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 7 x Over 3 minus x EndFraction) OverOver 3 minus (StartFraction 7 x Over 3 minus x EndFraction) EndEndFraction = x StartStartFraction 3 (StartFraction 7 x Over 3 minus x EndFraction) OverOver (StartFraction 7 x Over 3 minus x EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 3 x Over x + 7 EndFraction) OverOver 3 minus (StartFraction 3 x Over x + 7 EndFraction) EndEndFraction = x StartStartFraction 3 (StartFraction 3 x Over x + 7 EndFraction) OverOver (StartFraction 3 x Over x + 7 EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 7 x Over 3 minus x EndFraction) OverOver 3 minus (StartFraction 7 x Over 3 minus x EndFraction) EndEndFraction = 0 StartStartFraction 3 (StartFraction 7 x Over 3 minus x EndFraction) OverOver (StartFraction 7 x Over 3 minus x EndFraction) + 7 EndEndFraction = StartStartFraction 7 (StartFraction 3 x Over x + 7 EndFraction) OverOver 3 minus (StartFraction 3 x Over x + 7 EndFraction) EndEndFraction = 0

Mathematics
2 answers:
Svetlanka [38]3 years ago
3 0

Answer:

B.

Step-by-step explanation:

slamgirl [31]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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I will make brainlyest.​
Temka [501]

Answer:

x + 46

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define expression</u>

4(-8x + 5) - (-33x - 26)

<u>Step 2: Simplify</u>

  1. Distribute:                              -32x + 20 + 33x + 26
  2. Combine like terms (x):         x + 20 + 26
  3. Combine like terms (Z):         x + 46
3 0
3 years ago
You should solve the answer for z not m pls
mariarad [96]

Step-by-step explanation:

we can factor out z

so that'll be

z((1/m)-(1/n))=1

divide by the value in parentheses on both sides

z=1/((1/m)-(1/n))

I can't tell if there's more the problem wants you to do. I could rewrite the equation on paper more easily, but I don't have one on hand

5 0
2 years ago
Read 2 more answers
Find the solution set of the inequality 14- 3x &lt; -1.14
Brrunno [24]

Answer:

14-3x<-1.14

-3x<-1.14-14

-3x<-15.14

x<5.04

8 0
3 years ago
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Y=2/x-3 make x the subject​
svp [43]
Multiply both sides by x - 3 to get :

y(x - 3) = 2

yx - 3y = 2

yx = 2 + 3y

x = (2 + 3y)/y

Hope this helps! Any questions let me know :)
7 0
3 years ago
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
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