Please please help me

Mathematics

1 answer:

Nataly_w [17]3 years ago

8 0

Answer:

The average rate of change is 4.

Step-by-step explanation:

It is 4 because when you do the formula to find the rate of change it comes out to be 4.

You might be interested in

What Is the slope line through (1,-1) and (5,-7)

Ksenya-84 [330]

Your slope should be 3/2

4 0

3 years ago

Read 2 more answers

Given △ABC. m∠A>m∠B>m∠C. Perimeter=30. Which side of △ABC may have length 7?

lisabon 2012 [21]

<u>Solution-</u>

As given in △ABC,

$m\angle A>m\angle B>m\angle C$

As from the properties of trigonometry we know that, the greater the angle is, the greater is the value of its sine. i.e

$\sin A>\sin B>\sin C$

According to the sine law,

$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$

In order to make the ratio same, even though m∠A>m∠B>m∠C, a must be greater than b and b must be greater than c.

$\Rightarrow a>b>c$

Also given that its perimeter is 30. Now we have to find out whose side length is 7. So we have 3 cases.

Case-1. Length of a is 7

As a must be the greatest, so b and c must be less than 7. Which leads to a condition where its perimeter won't be 30. As no 3 numbers less than 7 can add up to 30.

Case-2. Length of b is 7

As b is greater than c, so c must 6 or less than 6. But in this case the formation of triangle is impossible. Because the triangle inequality theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side. If b is 7 and c is 6, then a must be 17. So no 2 numbers below 7 can add up to 17.

Case-3. Length of c is 7

As this is the last case, this must be true.

Therefore, by taking the aid of process of elimination, we can deduce that side c may have length 7.

5 0

4 years ago

On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if

QveST [7]

Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure