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3 years ago

Please help me with this I BEG UU SM

Mathematics

2 answers:

PIT_PIT [208]3 years ago

8 0

WHEN THE IMPOSTOR IS SUS

pew pew pew pew pew pew pew, pew niu niu, PI PEW

Elan Coil [88]3 years ago

8 0

Answer:

Its D i think. If wrong then im sorry.

Step-by-step explanation:

You might be interested in

Don has 6 pieces of pipe. Each piece is 2 feet 6 inches long.

Alex777 [14]

Answer: 15 feet

Step-by-step explanation:

First you start with 2ft and 6in and convert it all into into inches.

If you know that 1 ft=12in then you know that 2 feet is the same as saying

12+12=24. If you don't understand use this chart-

1 ft=12in

2ft= 24in

3ft= 36in

4ft =48in

5ft= 60in

6ft= 72in

see I am counting by 12's.

Now take 2ft and convert it into inches. That would be 24 in (look in the chart).

now take the 24in(2ft) and add it to the 6in. So 24+6 =30

So now you know that one piece of pipe is 30in long.

But in the text it states that Don has 6 pieces, so...

because it says that he has 6 pieces of pipe then you are going to take that and multiply that number(6) by how long each piece is. look up and it shows how long each pieces is. They are all each 30in long. Take 30 and multiply that by 6 because there are 6 pipes and you will get 120in.

But it says that they need an answer of feet and inches or just feet if it exactly a some sort of foot like 43feet or 2 feet.

So then we are going to convert 180 into feet by dividing 180 by 12 and you get 15. So the answer is 15.

I hope this helps. Have fun learning!!

6 0

3 years ago

The Decimal System Uses 10 Symbols To Represent Numbers True or false

lutik1710 [3]

Answer:

For non-negative integers yes, it's 10 symbols.

Step-by-step explanation:

The symbols are the digits! 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.

Please note, that to represent negative numbers we use an additional symbol - and a . for fractions. I'm pretty sure the question is about the basics of the decimal system and the ten digits though.

7 0

2 years ago

Craig is practicing his baseball pitching he kept track of the speed oI made a histogram at right can you tell the speed of each

LenKa [72]

Step-by-step explanation:

I am not sure, if something else is missing.

but given that one chart we can say that Craig had 2 fastest throws.

they were in the category 70-75 mph.

but we cannot say precisely which one was faster, and how fast it went.

it is also not clear what is the categorization of a border element (e.g. with an exact speed of 60 mph - is it in the 55-60 or in the 60-65 category ? or both ?).

I assume the upper limit of each interval is included, and the lower limit is excluded.

under this assumption we can say the fastest pitch was faster than 70 mph but slower than or equal to 75 mph.

3 0

2 years ago

AT LEAST how many cubes like this one need to be joined together to form another LARGER SIZED CUBE?

Alex Ar [27]

Answer:

25?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago