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4 years ago

Simplify the expression: (− 2/3 pq^4)^2·(−27p^5q)

Mathematics

1 answer:

Allushta [10]4 years ago

8 0

Answer:

-12p^7q^9

Step-by-step explanation

-\left(-\frac{2}{3}pq^4\right)^2\cdot \:27p^5q

-27\cdot \frac{2^2p^2q^8}{3^2}p^5q

Multiply the fractions

\frac{2^2p^2q^8\cdot \:27p^5q}{3^2}

-\frac{2^2\cdot \:27p^7q^9}{3^2}

-2^2\cdot \:3p^7q^9

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Alecsey [184]

<h2>Coordinate Pairs</h2>

Coordinate pairs are organized like (x,y).

x tells us the location of the point in relation to the x-axis, the axis that is horizontal.
y tells us the location of the point in relation to the y-axis, the axis that is vertical.

To determine a coordinate pair, we can determine each coordinate individually, then put them together.

<h2>Solving the Question</h2>

Notice how the red point sits on the very edge of the graph.

When we look at the x-axis, we can see that it occurs at the number 0 on the x-axis. In other words, the red point occurs when x=0.

When we look at the y-axis, we can see that it lines up with the number 2. In other words, the red point occurs when y=2.

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<h2>Answer</h2>

(0,2)

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2 years ago

A department store has a discount on all shirts based on a percentage of the price. Suppose one shirt is marked down from $60 to

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Answer:

Step-by-step explanation: 45

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3 years ago

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gayaneshka [121]

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3 years ago

Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25

aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The mean time for the component failure is 2500 hours.

This means that $m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004$

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

$P(X > x) = e^{-0.0004*5000} = 0.1353$

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

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3 years ago

f the points (-4, 1) and (2, 1) are the endpoints of a diameter of a circle, where is the center? A) (-7, 1) B) (-1, 1) C) (1, -

Ulleksa [173]

Answer:

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The centre is at the midpoint of the endpoints of the diameter.

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