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3 years ago

How do I solve y= -3(1/2)*2 ?

Mathematics

2 answers:

Kruka [31]3 years ago

6 0

Idk how to do this one

mr Goodwill [35]3 years ago

3 0

The answer is -3
(1/2)*2=1 -3*1=-3 So, Y=-3

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A vial holds 2 milliliters of pixie dust.

Alina [70]

Hi your answer would be 6 1/2 vials of pixie dust!

5 0

2 years ago

Find the degree measure of each angle in the triangle.

Alex777 [14]

Answer:

∠R = 56°
∠Q = 90°
∠S = 34°

Step-by-step explanation:

The given triangle is a right angled triangle.

So, the angles in the triangle are :

90°
(2x + 38)°
(5x - 11)°

Solving according to <u>angle sum property</u>,

Sum of all angles in a triangle is 180°

$\longrightarrow$ 90° + (2x + 38)° + (5x - 11)° = 180°

$\longrightarrow$ 117° + 7x = 180°

$\longrightarrow$ 7x = 180° - 117°

$\longrightarrow$ 7x = 63°

$\longrightarrow$ x = 9

Angles =

$\longrightarrow$ 2(9) + 38

$\longrightarrow$ 56°

$\longrightarrow$ 5(9) - 11

$\longrightarrow$ 34°

∠R = 56°
∠Q = 90°
∠S = 34°

The angles are 56°, 90° and 34°.

4 0

2 years ago

A rectangle is 8 inches long and 4 inches wide. A similar rectangle is 16 inches long. What is the width of the second rectangle

Shkiper50 [21]

8 × 2 = 16 so..... 4 × 2 = 8

the width is 8 inches

4 0

3 years ago

This table shows the number of customers who have come in to Trent’s Hobby Shop each day since he opened the doors.

Alona [7]

Since both the input and the output assume only integer values, the function is classified as discrete.

<h3>What are continuous and discrete variables?</h3>

Continuous variables: Can assume decimal values, hence they are represented by rational numbers.

Discrete variables: Assume only countable values, such as 1, 2, 3, …, hence they are represented by whole numbers, or even integers if it can be negative.

In this problem, all values on the table assume only integer values, hence the function is classified as discrete.

More can be learned about classification of variables at brainly.com/question/16978770

#SPJ1

3 0

1 year ago

WILL GIVE BRAINLIEST!!!!

Vesna [10]

$(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =$

$= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}$

$= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}$

$= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}$

$= 2^{-16-12+28} \times 5^{10-8}$

$= 2^{0} \times 5^{2}$

$= 1 \times 25$

$= 25$

7 0

2 years ago