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lesya [120]
3 years ago
11

How do I solve y= -3(1/2)*2 ?

Mathematics
2 answers:
Kruka [31]3 years ago
6 0
Idk how to do this one
mr Goodwill [35]3 years ago
3 0
The answer is -3
(1/2)*2=1 -3*1=-3 So, Y=-3
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A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an a
storchak [24]

Answer:  267.

Step-by-step explanation:

When there is no prior information for the population proportion, then the formula we use to find the sample size to estimate the confidence interval :

n=0.25(\dfrac{z^*}{E})^2 , where z* = Critical z-value and E + amrgin of error.

Let p = proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label.

Since , we have no prior information about p. so we use above formula

with E = 0.06 and critical value for 95% confidence =z* =1.96  [By z-table ] , we get

n=0.25(\dfrac{1.96}{0.06})^2=0.25(32.6666)^2\\\\=(0.25)(1067.111111)\\\\=266.777777778\approx267

Hence, the required sample size is 267.

7 0
3 years ago
Rotate rectangle ABCD 90ºccw about the origin. What<br> are the image coordinates?
bazaltina [42]

Answer:

Step-by-step explanation:

1. When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.

2. The rule for a rotation by 180° about the origin is (x,y)→(−x,−y) .

3. Rotation of a point through 180°, about the origin when a point M (h, k) is rotated about the origin O through 180° in anticlockwise or clockwise direction, it takes the new position M' (-h, -k). ...

7 0
3 years ago
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

5 0
1 year ago
Which list shows the numbers in order from least to greatest?
dem82 [27]

Answer:

7.41, 7.6, 745

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
Eva is at a sushi restaurant. She ordered 2 pieces of squid for a total of $3.50, 1 piece of eel for $3.25, 3 pieces of tuna for
earnstyle [38]
2 pieces of squid = $3.50 
Therefore 1 piece of squid = $1.75 (3.50÷2)

1 piece of eel = $3.25

3 pieces of tuna = $6.75
Therefore 1 piece of tuna = $2.25 (6.75÷3)

4 pieces of crab = $8.00 
Therefore 1 piece of crab = $2 (8÷4)

Put them in order of price and you get 

$1.75 , $2 , $2.25 , $3.25
squid,crab,tuna,eel
5 0
3 years ago
Read 2 more answers
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