Find the equation, f(x) = a(x-h)2 + k, for a parabola that passes through the point (8,12) and has (6,10) as its vertex. What is
the standard form of the equation?
1 answer:
For the x value flip the sign
f(x)=a(x-6)^2+10
Find a
12=a(8-6)^2+10
12=4a+10
12-10=4a
2=4a
a=2/4
a=0.5
y=0.5(x-6)^2+10
Hope that helps
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Answer:
The equation would be:
(X+1)^2 + (y-1)^2 = 9
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14 + 6 = 20
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X/4 + 1 = -6
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Answer:
80 cookies
Step-by-step explanation:
25% of 64 is 16
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