The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Range=±7%
Martin=71%, Lang=29%
Range for Martin=71%±7%
So, highest %=71%+7%=78%
Lowest %=71%-7%=64%
Therefore,range for Martin is between 64%-78% which is 14%
Answer:
The answer is noncollinear
Step-by-step explanation:
My guess would be A ! Hope this helps
Answer:
It will be A
Step-by-step explanation:
Hope this helped you out
