<span>A. 3(6)-1/2(6)+1 this is the answer
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Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
Answer:
x = 100√3
Step-by-step explanation:
tan(30º) = x/300
x = 300 tan(30º)
x = 300/√3
x = 100√3
Answer:
Multiply the divisor by a power of 10 to make it a whole number.
Multiply the dividend by the same power of 10. Place the decimal point in the quotient.
Divide the dividend by the whole-number divisor to find the quotient.
