It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4
There are 10 options for the first "1" and only 1 option for the other two 1's
There are 9 remaining options for the first "2" and only 1 option for the other 2
There are 8 remaining options for the first "3" and only 1 option for the other 3
There are 7 remaining options for the "4"
10 x 1 x 1 x 9 x 1 x 8 x 1 x 7
10 x 9 x 8 x 7 = 5,040
Answer: 5,040
Carl has two more flips and we want to know the probability that one and only of those times it will be jelly side up. assuming the basic head and tails probability each flip we have 4 possible;e outcomes: Plain side Plain side, Plain side Jelly side, jelly side Plain side and jelly side jelly side and 2 of those four give us the one P wanted, so 2/4 = 50% probability.
You could expect about 1,248 students to play at least 4 hours every week.
Our tables have 100 students involved. All but 4 of the students are in the category of at least 4 hours. That is 96%.
Therefore, we simply need to multiply 0.96 by 1300 to get the estimated amount.
0.96 x 1300 = 1248
Answer:
A = $ 4188.38
Step-by-step explanation:
A= $2500
r = 3.5% = 0.035
t = 15years
n = 1

