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n200080 [17]
3 years ago
8

Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written using

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

f(x) = - 3x + 4

Step-by-step explanation:

Given

9x + 3y = 12

We require to rearrange expressing y in terms of x

Subtract 9x from both sides

3y = - 9x + 12 ( divide all terms by 3 )

y = - 3x + 4

Expressed in functional notation by replacing y by f(x), that is

f(x) = - 3x + 4

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What is the positive solution to 4x2 + 2x= 42? NEED HELP
VikaD [51]

Answer:

Step-by-step explanation:

first multiply 4 X 2= 8

8+2x=42

Now you are going to pass 8 to the other side by adding -

2x=42-8

2x=34

Now you are going to divide 34 between 2 to eliminate the 2 multiplying in the other side. 34 between 2= 17

X=17

Hope this helps :)

7 0
3 years ago
If an angle measures between 90 and 180, how is it classified
sukhopar [10]

The name of the angle is obtuse

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What is the starting number is this puzzle? +7 -4 x3 =30
GarryVolchara [31]

Answer:

35+7-3x4=30

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2 years ago
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IF YOUR GOOD AT MATH THEN PLEASE ANSWER THIS !!!
harina [27]

Answer:

The answer is A

Step-by-step explanation:

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7 0
2 years ago
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(d) 2n + 1 is an odd number. Show that the product of 2 consecutive odd numbers is always an odd number
posledela

n^{2}First, understand that 2n+1 means that 2 times any number plus 1 will be an odd number. You can try this out. If you plug in any number, multiply it by 2 and add 1 it will be odd.

Second, consecutive odd integers are always two numbers apart.

3,5,7,9, etc...

3+2 = 5

5+2 = 7

7+2 = 9  etc...

So two consecutive odd integers can be written as:

2n+1 and (2n+1) +2

we can simplify   (2n+1) +2   into   2n +3

the product of two consecutive odd integers would be

(2n+1) x (2n+3)

if we distribute this we get:

4n^{2}+6n + 2n +3

= 4n^{2}+8n +3

What we can do now is separate the +3 into +1 and +2

4n^{2}+8n +3

4n^{2}+8n +2 +1

Now we can factor out a 2 from the equation

2(2n^{2}+4n +1) +1

Now you can see that we have the equation:

2 times some number + 1

No matter what (2n^{2}+4n +1) is, if we multiply it by 2 and add 1, it will be odd.

So we have proven that the product 2 consecutive odd integers is odd.

5 0
3 years ago
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