All categories

3 years ago

Use the information given to write an equation in standard form (If possible please show work)

Mathematics

1 answer:

Effectus [21]3 years ago

6 0

Answer:

-2x + y = -1.

Step-by-step explanation:

The slope of the line = rise / run

= (11-9) / (6-5) = 2.

The point-slope form of the line is

y - y1 = 2(x - x1) where (x1, y1) is a point on the line so we have:

y - 11 = 2(x - 6) ( using the point (6, 11)

y = 2x - 12 + 11

y = 2x - 1

Convert to standard form:

-2x + y = -1.

You might be interested in

Please solve for x z=m+x

SIZIF [17.4K]

Answer:

x = z - m

Step-by-step explanation:

Solving for x with steps:

z=m+x
x + m = z
x + m - m = z - m
x = z - m

3 0

4 years ago

Peter rides a bike along a triangular path in the neighborhood park. The sides of the path measure 3.36 miles, 4.18 miles, and 5

Molodets [167]

Answer:

The distance that Peter rides is:

13.15 miles.

Step-by-step explanation:

To identify the miles that Peter rides, you must imagine the triangle with measures: 3.36 miles, 4.18 miles, and 5.61 miles. How you can suppose, Peter regularly rides exactly by each side of the triangle mentioned, then you must find the perimeter of the triangle to identify the miles that Peter rides, remember that the perimeter of an irregular triangle is:

Perimeter of a triangle = side + side + side

If you replace the formula, you obtain:

Perimeter of a triangle = 3.36 miles + 4.18 miles + 5.61 miles
Perimeter of a triangle = 13.15 miles

6 0

3 years ago

8.7 × 10 to the 5th power in standard form

Andrej [43]

Answer would be 870000

6 0

4 years ago

Read 2 more answers

Which orderd pair is a solution of the equation-3x+5y = 2x + 3y

velikii [3]

Answer:

2y=5x

Step-by-step explanation:

-3x+5y=2x+3y

5y=5x+3y

2y=5x

4 0

3 years ago

What are the real zeros of the function g(x)=x^3+2x^2-x-2

Gre4nikov [31]

$g(x)=x^3+2x^2-x-2\\\\\text{The zeros:}\\\\g(x)=0\to x^3+2x^2-x-2=0\\\\x^2(x+2)-1(x+2)=0\\\\(x+2)(x^2-1)=0\iff x+2=0\ \vee\ x^2-1=0\\\\x+2=0\ \ \ |-2\\x=-2\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt{1}\to x=-1\ \vee\ x=1\\\\\text{Answer:}\ x=-2\ or\ x=-1\ or\ x=1$

4 0

3 years ago