Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,

or, 
or, 
or, 
or, 
Substituting the value of
in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
Answer:
A: Step 1: 6x − 10 = 1; Step 2: 6x = 11
Step-by-step explanation:
First: remove parentheses by multiplying factors.
6x - 10 = 1
Second: Move the constants to the right side of the equation
6x = 1 + 10
6x = 11