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mojhsa [17]
3 years ago
14

Which point is a solution to the linear inequality below:

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

A (0,0)

Step-by-step explanation:

y - 3x < 1

0 - 3(0) < 1

0 < 1

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If you had a billion dollars and you spend one dollar every second how many years would it take you to spend it all
trapecia [35]

Answer: 31.71 years

Step-by-step explanation:

First, we need to find how many seconds are in a day.

There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute.

There are 3,600 seconds in an hour. How did we find this? 60 (min) x 60 (sec)

There are 86,400 seconds in a day. 24 (hr) x 3,600 (sec)

Now we need to find how many seconds are in a year.

There are 365 days in a year, we can multiply that by 86,400.

365 x 86,400 = 31,536,000

Whew! Now that we have that out the way, we can now divide $1 billion by 31,536,000 seconds.

1,000,000,000/31,536,000 = 31.71 (rounded to the nearest hundredth)

If you had a billion dollars, it will take 31.71 years to spend one dollar every second.

3 0
3 years ago
Read 2 more answers
Can someone help me with this?
Mandarinka [93]

Answer:

Step-by-step explanation:

Area of rectangle = length * width

                             = (x + 4) (5x)

                             = x *5x + 4 *5x

                            = 5x² + 20x

Perimeter of rectangle = 2*(length + width)

                                     = 2*(x + 4 + 5x)

                                     = 2*(6x + 4)

                                   = 2*6x + 2 *4

                                     = 12x + 8

4 0
3 years ago
Find the value of sin 0<br>cos(90°- 0) + cos 0 sin(90°-0)​
Step2247 [10]

Step-by-step explanation:

sin \theta \: cos(90 \degree - \theta) + cos \theta \: sin(90 \degree - \theta) \\  = sin(\theta + 90 \degree - \theta) \\  = sin(90 \degree)  \\  = 1

5 0
4 years ago
Does anyone know how to solve this?
Lilit [14]

The pattern is that the numbers in the right-most and left-most squares of the diamond add to the bottom square and multiply to reach the number in the top square.


For example, in the first given example, we see that the numbers 5 and 2 add to the number 7 in the bottom square and multiply to the number 10 in the top square.


Another example is how the numbers 2 and 3 in the left-most and right-most squares add up to the number 5 in the bottom square and multiply to the number 6 in the top square.


Using this information, we can solve the five problems on the bottom of the paper.


a) We are given the numbers 3 and 4 in the left-most and right-most squares. We must figure out what they add to and what they multiply to:

3 + 4 = 7

3 x 4 = 12

Using this, we can fill in the top square with the number 12 and the bottom square with the number 7.


b) We are given the numbers -2 and -3 in the left-most and right-most squares, which again means that we must figure out what the numbers add and multiply to.

(-2) + (-3) = -5

(-2) x (-3) = 6

Using this, we can fill the top square in with the number 6 and the bottom square with the number -5.


c) This time, we are given the numbers which we typically find by adding and multiplying. We will have to use trial and error to find the numbers in the left-most and right-most squares.


We know that 12 has the positive factors of (1, 12), (2,6), and (3,4). Using trial and error we can figure out that 3 and 4 are the numbers that go in the left-most and right-most squares.


d) This time, we are given the number we find by multiplying and a number in the right-most square. First, we can find the number in the left-most square, which we will call x. We know that \frac{1}{2}x = 4, so we can find that x, or the number in the left-most square, is 8. Now we can find the bottom square, which is the sum of the two numbers in the left-most and right-most squares. This would be 8 + \frac{1}{2} = \frac{17}{2}. The number in the bottom square is \boxed{\frac{17}{2}}.


e) Similar to problem c, we are given the numbers in the top and bottom squares. We know that the positive factors of 8 are (1, 8) and (2, 4). However, none of these numbers add to -6, which means we must explore the negative factors of 8, which are (-1, -8), and (-2, -4). We can see that -2 and -4 add to -6. The numbers in the left-most and right-most squares are -2 and -4.

4 0
4 years ago
1
Lina20 [59]

Answer:

\textbf{The slope of the parallel line is given by $ 2 $}\\

Step-by-step explanation:

\textup{The slope of any two parallel lines are equal and they only differ in their $y- intercepts$. }\\\textup{Given $y = 2x + 4 $}\\\textup{This is  comparable to $y = mx + c$, where $m$ is the slope of that line.}\\\textup{Therefore, the slope of the given line and any line parallel to it is $ 2$.}

7 0
3 years ago
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