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Tanzania [10]
3 years ago
10

If 10 is added to each observation and the following data set what is the relationship between the original standard deviation a

nd the new standard deviation
1 5 9 15 27 32
A the original standard deviation is 10 times the new standard deviation
B the original standard deviation is equal to the new standard deviation
C the new standard deviation is 10 times the original standard deviation
D the new standard deviation is 10 times more than the original standard deviation
Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

g

Step-by-step explanation:

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How many ways can you choose 4 cookies from a cookie jar containing 25 cookies of all the same type?
andre [41]

Answer:

Only one.

Step-by-step explanation:

Given that there are 25 cookie of the same type in a cookie jar.

We have to select 4 cookies from these 25.

Since they are all the same type, they are identical.

The question is

How many ways can you choose 4 cookies from a cookie jar containing 25 cookies of all the same type?

There is no difference if we take any four cookies from these 25.

Hence no of different ways = 1

Only one is the answer.

6 0
4 years ago
Read 2 more answers
Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca
KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0
4 years ago
I really need help with this chart !! 20 points !!
vichka [17]
Lean is 5 and the quasretiv
5 0
4 years ago
Find a counterexample to show that the statement is false. Assume all sets are subsets of a universal set U = {1, 2, 3, 4, 5}. (
natka813 [3]

Answer:

For subsets A={1,2},B={2,3},C={1,2 5} of U = {1, 2, 3, 4, 5}.

A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

Step-By-Step Explanation:

U = {1, 2, 3, 4, 5}.

A={1,2}

B={2,3}

C={1,2 5}

For the Left Hand Side

B-C={3}

A ∪ (B − C)= {1,2} ∪ {3} ={1,2,3}

Likewise, the Right Hand Side:

(A ∪ B)={1,2,3}

(A ∪ C)={1,2,5}

(A ∪ B)- (A ∪ C)= {1,2,3}-{1,2,5}={3}

Since, {1,2,3} ≠ {3}, A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

7 0
3 years ago
5. A painter uses paint and thinner in the ratio 60:40. He uses 15 litres of paint to paint a house. How much thinner will he us
JulijaS [17]
60u=15 litres
1u=15l÷60
=0.25l
40u=0.25l×40u
=10l
Ans:10 litres of paint thinner
3 0
4 years ago
Read 2 more answers
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