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3 years ago

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What is an equivalent ratio of 5:2

2 answers:

avanturin [10]3 years ago

8 0

<span>an equivalent ratio of 5:2
= 10:4
= </span>15:6
= 20:8
= 25:10
= 30:12

S_A_V [24]3 years ago

6 0

An equivalent ratio would be 10:4 and so would 50:20

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solong [7]

The answer is D). 125 = 1.28f. This accounts for both sales tax and the cost of food.

3 0

2 years ago

Show work<br> Find the volume of the pyramid

Burka [1]

<u></u><em>Hello there, and thank you for posting your question here on brainly.

______________________________________________________________
Answer: 128
</em><em>Why?
</em><em>______________________________________________________________
To find the volume of a cylinder, we have to use the formula lwh/3. The length is 8, width is 4, and height is 12. So we have to multiply all of those together, then divide by 3. (8 * 4 = 32) -> (32 * 12 = 384) -> (384/3 = 128) The volume is 128.

</em><em>Hope this helped you! ♥</em><em>
</em>

3 0

3 years ago

The length of a rectangle is 4 units less than the width. The area of the rectangle is 21 units. What is the length, in units, o

bazaltina [42]

The formula of an area of a rectangle:

A = wl

We have l = w - 4 and A = 21.

Substitute:

w(w - 4) = 21 <em>use distributive property</em>

(w)(w) + (w)(-4) = 21

w² - 4w = 21 <em>subtract 21 from both sides</em>

w² - 4w - 21 = 0

w² - 7w + 3w - 21 = 0

w(w - 7) + 3(w - 7) = 0

(w - 7)(w + 3) = 0 ↔ w - 7 = 0 ∨ w + 3 = 0

w = 7 ∨ w = -3 < 0

l = w - 4 → l = 7 - 4 = 3

<h3>Answer: the length = 3 u.</h3>

4 0

3 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

The answer and how to do it.

Kruka [31]

let x = orginal price of the shorts

$21 = x(100%-20%) * 1.05

$21 = x(80%) * 1.05

$21 = 0.8x * 1.05

Subtract 1.05 from both sides

$19.95 = 0.8x

Divide 0.8 from both sides

$24.9375 = x

So the orginal price of the shorts are about $24.94

4 0

3 years ago