Answer:
y-1=-2/3(x+9)
Step-by-step explanation:
y-1=-2/3(x-(-9))
y-1=-2/3(x+9)
Answer:
D
Step-by-step explanation:
First add all the simple line up so;
Then use Pythagoras to work out the lengths of the remaining lines
So to three decimal places it would be;
Answer:
Step-by-step explanation:
Hi there!
Slope-intercept form: 
where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)
<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>
where two points that fall on the line are 
and 
On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:
Therefore, the slope of the line is 3. Plug this into :
<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>
Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into :
I hope this helps!
<span>Let the number of nickles be x
Let the number of pennies be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
nickles x $0.05 $0.05x
pennies y $0.01 $0.01y
-------------------------------------------
TOTALS 56 ----- $1.52
The first equation comes from the second column.</span>
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
