-(7x + 2) - 8x + 1 x=5

Are the following triangles similar? Justify your answer.

Readme [11.4K]

if the triangles are indeed similar, then their corresponding sides will yield the same proportion or ratio, let's check, △MDC has 3 sides, a small one a medium and a large, same is true for △LON, so let's use hmmm say the small side of each and the medium side of each, to see if their ratio matches. Check the picture below.

6 0

3 years ago

Andre has 4 times as many model cars as Peter, and Peter has one-third as many model cars as Jade. Andre has 36 model cars. Writ

PilotLPTM [1.2K]

1) Name the variables:

A: number of model cars Andre has

P: number of model cars Peter has

J: number of model cars Jade has.

2) Statements:

Andre has 4 times as many model cars as Peter: A = 4 P

Peter has one-third as many model cars as Jade: P = J / 3

Andre has 36 model cars: A = 36

3) Write and solve an equation to find how many model cars Peter has.

A = 4P => A/4 = P

=> P = A / 4

=> P = 36 / 4 = 8

4) Using your answer from part a, write and solve an equation to find how many model cars Jade has.

P = J / 3 => J = 3P

=> J = 3 (8) = 24

4 0

3 years ago

"Fifty-seven more than two times j"

castortr0y [4]

Answer:

2j+57

Step-by-step explanation:

Two times a umber j is expressed as 2j

if Fifty-seven is more than two times j", this means we will have to add 57 to 2j as shown;

f(j) = 2j + 57

Hence the statement written as a function is expressed as 2j+57

7 0

3 years ago

What is the product of 7 and 1 and three fourths?

Marat540 [252]

7 * 1 3/4
7 * 1 = 7
7 * 3/4 = 21 / 4 = 5.25
7 + 5.25 = 12.25

3 0

4 years ago

Read 2 more answers

Elwin Osbourne, CIO at GFS, Inc., is studying employee use of GFS e-mail for non-business communications. A random sample of 200

ladessa [460]

Answer:

The 90% confidence interval for the population proportion is

(0.10872, 0.19128)

Step-by-step explanation:

Explanation:-

Step(i):-

Given data A random sample of 200 e-mail messages was selected. Thirty of the messages were not business related

Given random sample size 'n' = 200

Given Thirty of the messages were not business related

let 'x' = 30

Probability of the messages were not business related or proportion

$p = \frac{x}{n} = \frac{30}{200} = 0.15$

Step(ii):-

The 90% confidence interval for the population proportion is

$(p - Z_{0.10} \sqrt{\frac{p(1-p)}{n} } , p + Z_{0.10} \sqrt{\frac{p(1-p)}{n} } )$

Level of significance ∝ = 0.90 or 0.10

The critical value Z₀.₁₀ = 1.645

The 90% confidence interval for the population proportion is

$( 0.15-1.645 \sqrt{\frac{0.15(1-0.15)}{200} } , 0.15 +1.645 \sqrt{\frac{0.15(1-0.15)}{200} } )$

on calculation, we get

(0.15 - 0.04128 , (0.15 + 0.04128)

(0.10872, 0.19128)

Conclusion:-

The 90% confidence interval for the population proportion is

(0.10872, 0.19128)

5 0

3 years ago