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3 years ago

Is 1.61 kilometers a foot

Mathematics

1 answer:

Alex73 [517]3 years ago

6 0

No, it's a little more than that.

1.61 kilometers is 5,282.2 feet.

That's about 2.2 feet longer than 1 mile.

You might be interested in

Which value is equivalent to 48 ÷ ((2 + 6) × 2) − 1? A) -12 B) 2 C) 3 1 5 D) 3

timama [110]

Answer:

B) 2

Step-by-step explanation:

Given expression,

48 ÷ ((2 + 6) × 2) − 1

In simplification we follows the following order,

B = Bracket

O = Of

D = Division

M = Multiplication

A = Addition,

S = Subtraction,

Thus, steps of solving the given expression by following BODMAS are as follow,

$\frac{48}{(2 + 6) \times 2}-1$

$=\frac{48}{8\times 2}-1$

$=\frac{48}{16}-1$

$=3-1$

$=2$

Hence, OPTION B is correct.

6 0

4 years ago

What is. 9 divided by 204

gulaghasi [49]

Is that .9? or was that period mark accidental?

8 0

4 years ago

A random sample of 100 teletype operators indicates that their salaries fluctuate quite a bit. The sample Standard deviation of

ELEN [110]

Answer:

$\frac{(99)(10)^2}{123.225} \leq \sigma^2 \leq \frac{(99)(10)^2}{77.046}$

$80.341 \leq \sigma^2 \leq 128.495$

Now we just take square root on both sides of the interval and we got:

$8.963 \leq \sigma \leq 11.336$

Step-by-step explanation:

Data given and notation

s=10 represent the sample standard deviation

$\bar x$ represent the sample mean

n=100 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical values.