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3 years ago

6

4/5 of the cake was left, but after Brian ate some only 1/4 of the cake was left. Which fraction of the cake did Brian eat?

1 answer:

LiRa [457]3 years ago

7 0

Answer:

3/4

Step-by-step explanation:

there was 4/5 you just had to minis 3and 4

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If the coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6), the x-intercept of is (3, 0) (18/5, 0) (9,

tester [92]

The x-intercept of CD=18/5,0
Point lies on CD=32,-71

6 0

3 years ago

Read 2 more answers

24 students brought her permission slips to attend the class field trip is this represent at 8:10 to the class how many students

OlgaM077 [116]

Answer:

30 students

Step-by-step explanation:

24 over 80 is equal to x over 100

cross multiply and you get

80x =240

divide 80 on both sides

you get 3

add an extra sero

4 0

3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

This is part one of the problem posting part two after this

tatiyna

Answer:

new image should be 4 x 8

post the pictures for the questions

Step-by-step explanation:

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

7 0

3 years ago

Shirley has a collection of 50 stamps and adds 4 stamps daily to her collection. model this situation as a function of number of

kompoz [17]

Stamps - S

S= 50+ 4d

Sorry if I’m wrong

4 0

2 years ago