Answer:
there are 2 bricks.
Step-by-step explanation:
well, p + (-2), now a sign in front of a grouping symbol usually means it has a 1*, so +(, really means +1*, thus p + (-2) really means p + 1*(-2), which gives us p - 2, and that'd be ordinally, 2 numbers to the left of "p".
likewise, 5 + p, is just the same as p + 5, so that value will be a number 5 numbers to the right of "p".
just as above, p + 1, is just one value to the right of "p".
![\bf \rule[0.35em]{2em}{0.25pt}\stackrel{p-2~\hfill }{|\rule[0.35em]{2em}{0.25pt}}|\rule[0.35em]{2em}{0.25pt}\boxed{P}\stackrel{~\hfill p+1}{\rule[0.35em]{2em}{0.25pt}|}\rule[0.35em]{2em}{0.25pt}|\rule[0.35em]{2em}{0.25pt}|\rule[0.35em]{2em}{0.25pt}|\stackrel{~\hfill p+5}{\rule[0.35em]{2em}{0.25pt}|}\rule[0.35em]{2em}{0.25pt}|](https://tex.z-dn.net/?f=%5Cbf%20%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%5Cstackrel%7Bp-2~%5Chfill%20%7D%7B%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7D%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%5Cboxed%7BP%7D%5Cstackrel%7B~%5Chfill%20p%2B1%7D%7B%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%7D%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%5Cstackrel%7B~%5Chfill%20p%2B5%7D%7B%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C%7D%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D%7C)
To find the width, divide the area by the length.
Width = 9/10 / 2/5
When dividing fractions flip the second one over and multiply:
Width = 9/10 x 5/2 = (9 x5) / (10 x 2) = 45/20 = 2 and 1/4 miles.
Answer:
Scalar product
Step-by-step explanation:
The scalar product of a matrix refers to the product of a matrix and a number. The scalar is used to multiply each element in the matrix to get the final vector. In the question the scalar is k which is a constant and the matrix is A.
in the example below 2 is the scalar
![2*\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://tex.z-dn.net/?f=2%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D)
the final matrix will be
![\left[\begin{array}{ccc}2&4&6\\8&10&12\\14&16&18\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%264%266%5C%5C8%2610%2612%5C%5C14%2616%2618%5Cend%7Barray%7D%5Cright%5D)
The first step to solving this expression is to factor out the perfect cube
![\sqrt[3]{m^{2} n^{3} X n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B2%7D%20%20n%5E%7B3%7D%20X%20n%5E%7B2%7D%20%20%20%7D%20)
The root of a product is equal to the product of the roots of each factor. This will make the expression look like the following:
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
Finally,, reduce the index of the radical and exponent with 3
n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%20%7D%20)
This means that the correct answer to your question is n
![\sqrt[3]{ m^{2} n^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20m%5E%7B2%7D%20n%5E%7B2%7D%20%7D%20)
.
Let me know if you have any further questions
:)