All categories

4 years ago

Which statement correctly describes the phosphate ion, PO4/3-?

2 answers:

8 0

I believe the correct answer from the choices listed above is the first option. Phosphate ion is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion. Hope this answers the question. Have a nice day.

Vladimir [108]4 years ago

6 0

The correct answer is (a)

It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion.

The explanation:

- the bond between oxygen and phosphorus is covalently.

when A covalent bond is a bond in which electrons are shared. \nd the ionic bond, electrons are completely transferred. In this case phosphate ion (PO4)-3 is covalent.

- that's means that the choice C and D don't be the correct answer.

-Additionally, since the charge is on the oxygen atoms due to the bonding with phosphorus, so we can say that the charge is on the entire ion and not just on the phosphorus atom so,the answer B also not the correct answer.

and the correct one is (A)

You might be interested in

Blue colour of cupric nitrate on strongly heating gives gives black cupric oxide powder along with oxygen gas and nitrogen dioxi

Zinaida [17]

Please see the image.

6 0

3 years ago

Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

saul85 [17]

Answer :

AgBr should precipitate first.

The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

Explanation :

$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

The solubility equilibrium reaction will be:

$CuBr\rightleftharpoons Cu^++Br^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][Br^-]$

$4.2\times 10^{-8}=0.073\times [Br^-]$

$[Br^-]=5.75\times 10^{-7}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgBr\rightleftharpoons Ag^++Br^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][Br^-]$

$7.7\times 10^{-13}=[Ag^+]\times 5.75\times 10^{-7}M$

$[Ag^+]=1.34\times 10^{-6}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{1.34\times 10^{-6}}{0.073}\times 100$

Percent of $Ag^+$ remains = 0.0018 %

3 0

3 years ago

What needed to be present in marine mud to form fossil fuels?

UkoKoshka [18]

When organisms and plants died and sank to the bottom of swamps and oceans, brown soil-like materials called peat are formed. Over millions of years, the peat became covered with sand, clay and other minerals and the peat is converted into layers of sedimentary rocks. After a long time, different type of fossil fuels are formed.

8 0

3 years ago

How does the freezing point of water from the ocean compare to distilled water one buys at the store?

Lelechka [254]

Due to prescence of any impurity, there will be change in physical properties of any liquid.

8 0

3 years ago

Read 2 more answers

How many significant figures does 0.005505 have

Viktor [21]

Answer:

it has six significant figures

8 0

3 years ago