When C-C is having a triple bond the hybridization is sp. But I am not sure how to relate that to the linear shape.
Answer:
The answer to your question is 24.325
Explanation:
Data
Magnesium-24 Abundance = 78.70%
Magnesium-25 Abundance = 10.13%
Magnesium-26 Abundance = 11.17%
Process
1.- Convert the abundance to decimals
Magnesium-24 Abundance = 78.70/100 = 0.787
Magnesium-25 Abundance = 10.13/100 = 0.1013
Magnesium-26 Abundance = 11.17/100 = 0.1117
2.- Write an equation
Average atomic mass = (Atomic mass-1 x Abundance 1) + (Atomic mass 2 x
Abundance-2) + (Atomic mass 3 x Abundance 3)
3.- Substitution
Average atomic mass = (24 x 0.787) + (25 x 0.1013) + (26 x 0.1117)
4.- Simplification
Average atomic mass = 18.888 + 2.533 + 2.904
5.- Result
Average atomic mass = 24.325
I think the correct answer would be A. When a polonium atom with 84 protons, 124 neutrons, and 84 electrons undergoes alpha decay, a lead atom would be produced with 82 protons, 122 neutrons, and 84 electrons together with an alpha particle having two protons and two neutrons.
Answer:
FALSE
Explanation:
Assuming that the gas is ideal
Therefore the gas obeys the ideal gas equation
<h3>Ideal gas equation is </h3><h3>P × V = n × R × T</h3>
where
P is the pressure exerted by the gas
V is the volume occupied by the gas
n is the number of moles of the gas
R is the ideal gas constant
T is the temperature of the gas
Here volume of the gas will be the volume of the container
Given the volume of the container and number of moles of the gas are constant
As R will also be constant, the pressure of the gas will be directly proportional to the temperature of the gas
P ∝ T
∴ Pressure will be directly proportional to the temperature
The volume of 1 mole of gas is always 22.4 dm3. Molar volume= Volume/number of moles (first we should discover the number of mole) so 22.4 =1/number of moles <=> number of moles=1/22.4 moles
Now that we know the number of moles we can use the formula Molar Mass= mass /number of moles <=> 254= mass/(1/22.4) so mass =254/22.4 <=> mass= 11.339 which is 11.3 g
