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3 years ago

What does the solution to the system c,p reprent in this situation 5c+4p=18.40 2c+4p=11.20

Mathematics

1 answer:

Natalka [10]3 years ago

7 0

Answer:

4 and 4/15=c. 2 and 2/15=p.

Step-by-step explanation:

I am younger than 12 i dont have much experience; done 2 or 3 problems like this...

first lets make it simpler...

2c+4p=11.20 is the same as c+2p=5.6

then subtract one from the other and you get 4c+2p=12.8

simplify again 2c+p=6.4

so the ratio of c to p is 2:1. Multiply 6.4 by 2/3 to get what c is... 64/15

64/15 is 4 and 4/15. then divide by 2 to get what p is so 64/15÷2=32/15 which is 2 and 2/15.

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Find the volume of the cone

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Find 6.75% of 260

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3 years ago

Find the cos A and tan B to four decimal places. URGENT

Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

Pythagoras theorem

$hypotenuse^{2}$ = $adjacent^{2}$ + $opposite^{2}$

$hypotenuse^{2}$ = $8^{2}$ + $5^{2}$

$hypotenuse^{2}$ = 64 + 25

hypotenuse = $\sqrt{89}$

hypotenuse = 9.4

a) Cos A

Data:

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Cos A = $\frac{8}{9.4}$

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A = $cos^{-1}$ (0.8511)

A = 31.7°

b) Tan B

Data:

Opposite = 8

Adjacent = 5

Formula:

Tan (Angle) = $\frac{opposite}{adjacent}$

Tan B = $\frac{8}{5}$

Tan B = 1.6

B = $cos^{-1}$ (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

#LearnwithBrainly

3 0

3 years ago

What is the cubed root of 275÷7

almond37 [142]

Step-by-step explanation:

It's an irrational number.

$\sqrt[3]{275:7}=\sqrt[3]{\dfrac{275}{7}}=\dfrac{\sqrt[3]{275}}{\sqrt[3]{7}}=\dfrac{\sqrt[3]{275}\cdot\sqrt[3]{7^2}}{\sqrt[3]{7}\cdot\sqrt[3]{7^2}}=\dfrac{\sqrt[3]{275\cdot49}}{\sqrt[3]{7\cdot7^2}}\\\\=\dfrac{\sqrt[3]{13475}}{\sqrt[3]{7^3}}=\dfrac{\sqrt[3]{13475}}{7}=\dfrac{1}{7}\sqrt[3]{13475}$

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3 years ago

-2 (m+n-4)+5 (-2m+2n)+n (m+4n-5)

Natalka [10]

So if you want to add
we distribute
a(b+c)=ab+ac so
-2(m+n-4)=-2m-2n+8

5(-2m+2n)=-10m+10n

n(m+4n-5)=mn+4n^2-5n

so total we ahve
-2m-2n+8-10m+10n+mn+4n^2-5n
group like terms
4n^2+-2m-10m-2n+10n-5n+mn+8
add like temrs
4n^2-12m+3n+mn+8

5 0

4 years ago

Solve for x and y. 4x-3y=16 -2x+4y=-2 DUE 2/7/17!

Trava [24]

$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$

Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
 $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$
$\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$
--------------------
$5y = 12$
$\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$

Let's replace the value found in the first equation:
$4x-3y=16\:(I)$
$4x-3*( \frac{12}{5}) =16$
$4x - \frac{36}{5} = 16$
least common multiple (5)
$\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$
$20x - 36 = 80$
$20x = 80 + 36$
$20x = 116$
$x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark$

4 0

4 years ago