Answer:
ΔE> E_minimo
We see that the field difference between these two flowers is greater than the minimum field, so the bee knows if it has been recently visited, so the answer is if it can detect the difference
Explanation:
For this exercise let's use the electric field expression
E = k q / r²
where k is the Coulomb constant that is equal to 9 109 N m² /C², q the charge and r the distance to the point of interest positive test charge, in this case the distance to the bee
let's calculate the field for each charge
Q = 24 pC = 24 10⁻¹² C
E₁ = 9 10⁹ 24 10⁻¹² / 0.20²
E₁ = 5.4 N / C
Q = 32 pC = 32 10⁻¹² C
E₂ = 9 10⁹ 32 10⁻¹² / 0.2²
E₂ = 7.2 N / C
let's find the difference between these two fields
ΔE = E₂ -E₁
ΔE = 7.2 - 5.4
ΔE = 1.8 N / C
the minimum detection field is
E_minimum = 0.77 N / C
ΔE> E_minimo
We see that the field difference between these two flowers is greater than the minimum field, so the bee knows if it has been recently visited, so the answer is if it can detect the difference
Answer:
Total Mass = 18 kg 900 gram
Explanation:
Given:
Mass of sugar buy = 6 kg 500 gram
Mass of rice buy = 12 kg 400 gram
Find:
Total Mass
Computation:
Total Mass = Mass of sugar buy + Mass of rice buy
Total Mass = 6 kg 500 gram + 12 kg 400 gram
Total Mass = 18 kg 900 gram
It will land at 14139.19 m away.
Explanation:
The expression for range d on level ground is given by;
d=v² sin (2Ф) /g where Ф is the fire angle and g is acceleration due to gravity
Given v=400m/s ,Ф= 60° and g=9.8 so,
d= 400² sin(120°) /9.8
d=(400²×0.86602540378) / 9.8
d=14139.19 m
Motion for falling object : brainly.com/question/11799308
Keyword : initial velocity, angle, range
#LearnwithBrainly
<h2>
Answer:</h2>
105146 Pa
<h2>
Explanation:</h2>
1) We will make a Free-Body Diagram representing all the upward and downward pressures exerted on the piston.
- Pressure exerted by the compressed spring (Pspring)
- Pressure due to weight of the piston (Pw)
- Atmospheric pressure (Patm)
- Initial pressure inside the cylinder. (P1)
2) We will formulate an equation balancing all upward and downward pressures.
P1= Patm + Pw + Pspring
3) We will calculate each of the pressures separately.
P = F/A
F= ks
k= 38×1000 =38000 N m
s= 2.5 /1000 = (2.5x10^-3) m
F = 38000×(2.5x10^-3) = 95 N
A = 30/10000 = (30x10^-4) m2
P = 95 / (30x10^-4)
Pspring ≅ 3167 Pa
P = F/A
F = W = mg
W = 2×9.81 = 19.62 N
A = 30/10000 = (30x10^-4) m2
P = 19.62 / (30x10^-4)
Pw = 654 Pa
P = 1atm = 101325 Pa
Patm = 101325 Pa
4) We will add all the downward pressures to reach the final answer (initial pressure inside the cylinder).
P1= Patm + Pw + Pspring
P1= 101325+654+3167
P1= 105146 Pa
field is force at a distnce = falling under grav ... contact is force at point of contact
