Answer:
Oc.
Explanation:
Velocity is a vector which also tells us direction, speed doesn’t.
Speed doesn’t represent the potential of an object.
As the cloud shrank, its gravitational potential energy was converted to kinetic energy and then into thermal energy.
Answer:
1. Direction of B is parallel to V
2. Magnetic field is most uniform between the flat, parallel magnetic poles of a c-shaped magnet
3. Doubling B would double the magnitude of the force on the proton
4. Magnetic field is strongest near the north and south poles
5. The initial direction of the proton is toward the right of the screen. The field deflects the proton toward the top of the screen
6. Assume that you are viewing the diagram on a flat computer screen. Perpendicular to the screen, pointing toward you.
7. A stationary point charge doesn’t generate a magnetic field in the space around it.
8. Proton enters magnetic field at a speed of 7.8 x 10^4, charge of proton equal to 1.6 x 10^-19 is 2.6 x 10^-14 N
9. A few times every million years
10. Magnitude |q|vB directed towards bottom of screen
Explanation:
Answer:
a) v = 54.7m/s
b) v = (58 - 1.66a) m/s
c) t = 69.9 s
d) v = -58.0 m/s
Explanation:
Given;
The height equation of the arrow;
H = 58t - 0.83t^2
(a) Find the velocity of the arrow after two seconds. m/s;
The velocity of the arrow v can be given as dH/dt, the change in height per unit time.
v = dH/dt = 58 - 2(0.83t) ......1
At t = 2 seconds
v = dH/dt = 58 - 2(0.83×2)
v = 54.7m/s
(b) Find the velocity of the arrow when t = a. m/s
Substituting t = a into equation 1
v = 58 - 2(0.83×a)
v = (58 - 1.66a) m/s
(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s
the time when H = 0
Substituting H = 0, we have;
H = 58t - 0.83t^2 = 0
0.83t^2 = 58t
0.83t = 58
t = 58/0.83
t = 69.9 s
(d) With what velocity will the arrow hit the surface? m/s
from equation 1;
v = dH/dt = 58 - 2(0.83t)
Substituting t = 69.9s
v = 58 - 2(0.83×69.9)
v = -58.0 m/s