Answer:
0.00185 Nm
Explanation:
Parameters given:
Width of loop = 10cm = 0.1m
Length of loop = 20cm = 0.2m
Current, I = 2.5 A
Magnetic field strength, B = 0.037 T
Magnetic torque, τ, is given as:
τ = N * I * A * B * sinθ
Where N = Number of turns (in this case 1)
θ = angle between magnetic field and perpendicular of loop (90°)
A = area of loop = length * width = 0.2 * 0.1 = 0.02 m²
τ = 1 * 2.5 * 0.02 * 0.037 * sin90
τ = 0.00185 Nm
