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dimulka [17.4K]
3 years ago
12

In a bag there are 2 red marbles, 3 white marbles and 5 blue marbles.  Once a marble is selected, it is NOT replaced. What is th

e value of probability of selecting three blue marbles?
Mathematics
2 answers:
eimsori [14]3 years ago
5 0
5 out of 10 or 50% is the answer
liq [111]3 years ago
3 0
Is there any answer options before deciding that you have?
i will then provide an answer.
You might be interested in
Express the confidence interval (0.036, 0.086) in the form of p-e< p
lina2011 [118]

Answer:

p-e< p < p+e

(0.061 - 0.025) < 0.061 < (0.061 + 0.025)

0.036 < 0.061 < 0.086

Step-by-step explanation:

Given;

Confidence interval CI = (a,b) = (0.036, 0.086)

Lower bound a = 0.036

Upper bound b = 0.086

To express in the form;

p-e< p < p+e

Where;

p = mean Proportion

and

e = margin of error

The mean p =( lower bound + higher bound)/2

p = (a+b)/2

Substituting the values;

p = (0.036+0.086)/2

Mean Proportion p = 0.061

The margin of error e = (b-a)/2

Substituting the given values;

e = (0.086-0.036)/2

e = 0.025

Re-writing in the stated form, with p = 0.061 and e = 0.025

p-e< p < p+e

(0.061 - 0.025) < 0.061 < (0.061 + 0.025)

0.036 < 0.061 < 0.086

6 0
3 years ago
. A carton of bolts weighs 7.8 pounds. How much does a carton containing 0.38 times as many bolts weigh?
Ber [7]
2.964 bolts
Because 7.8*.38=2.964
3 0
3 years ago
A specific shade of red nail polish requires 7 parts red to 2 parts yellow. A mixture contains 35 quarts of red and 8 quarts yel
slega [8]
Add 2 more parts of yellow
7=2
7=2
7=2
7=2
7=2
---------
35=10
3 0
4 years ago
Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)
marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

8 0
2 years ago
Find two consecutive whole numbers such that the sum of their squares is 221.
Law Incorporation [45]
n^2+(n+1)^2=2n^2+2n+1=221
2n^2+2n=220
n^2+n=110
n^2+n-110=0
(n-10)(n+11)=0\implies n=10,n=-11

But since n must be a whole number, we ignore n=-11. So the two integers are n=10 and n+1=11.
7 0
3 years ago
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