Complete Question
A survey is planned to estimate the proportion of voters who support a proposed gun control law. The estimate should be within a margin of error of 
with 99 %confidence, and we do not have any prior knowledge about the proportion who might support the law. How many people need to be included in the sample?
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The margin of error is 
From the question we are told the confidence level is 99% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of 
is
Here we will assume that the sample proportion of those who support a proposed gun control law to be 
because from the question they do not have any prior knowledge about the proportion who might support the law
Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=>
1. First calculate the positive root of the quadratic using your preferred formula. I got a solution 
. That gives you the distance the ball traveled from d=0 (small hill). So the answer is A.
2. The domain is [0,2.121...]. The range is from 0 to the max height. The d for which the ball is the highest is given by the formula x = -b / 2a = -3.3/(-3.2) = 1.031... so the max is 1.902... So the range is [0,1.902...] So the answer is C.
7x-3y=23
7x-3(-2)=23
7x+6 =23
-6. -6
7x=17
————
7. 7
x=2.42
