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Lunna [17]
3 years ago
5

write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)

Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0
m = \frac{y_{2} - y_{1}}{c_{2} - x_{1}} = \frac{-5 - 1}{7 - (-1)} = \frac{-6}{7 + 1} = \frac{-6}{8} = \frac{-3}{4} = -\frac{3}{4}

y - y₁ = m(x - x₁)
 y - 1 = ⁻³/₄[x - (-1)]
 y - 1 = ⁻³/₄(x + 1)
 y - 1 = ⁻³/₄(x) - ³/₄(1)
 y - 1 = ⁻³/₄x - ³/₄
    +1          + 1
      y = ⁻³/₄x + ¹/₄
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Study the figure.
tia_tia [17]

Answer:

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S=(r^2*π*a)/306°=

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Step-by-step explanation:

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4 0
3 years ago
What does 28+87÷3⋅2^3 equal
11111nata11111 [884]

Answer:

260

Step-by-step explanation:

28+29(23)

=28+(29)(8)

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7 0
3 years ago
Read 2 more answers
Subtract. –7 – 12<br> a. –19<br> b. –5<br> c. 5<br> d. 19
den301095 [7]
-7 - 12 = -1(7 + 12) = -1(19) = -19

Your answer is A.
8 0
3 years ago
What is the product of 2r2 - 5 and 3r
faust18 [17]

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Step-by-step explanation:

(3r) (2r^2 - 5)

Distribute.

6r^3 - 15r

Hope this helped.

8 0
3 years ago
Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did
vladimir1956 [14]

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

4 × Usha = 32

Usha = 8 i.e her number of books.

Mukat = 5×8=40.

I HOPE IT'S OK

6 0
3 years ago
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