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3 years ago

write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)

1 answer:

3 0

$m = \frac{y_{2} - y_{1}}{c_{2} - x_{1}} = \frac{-5 - 1}{7 - (-1)} = \frac{-6}{7 + 1} = \frac{-6}{8} = \frac{-3}{4} = -\frac{3}{4}$

y - y₁ = m(x - x₁)
y - 1 = ⁻³/₄[x - (-1)]
y - 1 = ⁻³/₄(x + 1)
y - 1 = ⁻³/₄(x) - ³/₄(1)
y - 1 = ⁻³/₄x - ³/₄
+1 + 1
y = ⁻³/₄x + ¹/₄

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The business college computing center wants to determine the proportion of business students who have personal computers (PC's)

Anastasy [175]

Answer:

Option A) reject null hypothesis if z is greater than 1.645

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 250

p = 30% = 0.3

Alpha, α = 0.05

Number of women belonging to union , x = 75

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.3\\H_A: p > 0.3$

This is a one-tailed(right) test.

Rejection Region:

$z_{critical} \text{ at 0.05 level of significance } = 1.645$

So, the rejection region will be

$z > 1.64$

That is we will reject the null hypothesis if the calculated z-statistic is greater than 1.645

Option A) reject null hypothesis if z is greater than 1.645

6 0

3 years ago

Theresa buys 62 stickers. She gives 6 stickers to her little sister. Theresa then splits the remaining stickers evenly across 8

Alja [10]

Answer:

7 stickers on each page.

Step-by-step explanation:

We start with 62 stickers.

Then we give 6 to the little sister, so we subtract 6 from 62.

62-6=56

Then we divide the remaining 56 stickers evenly across 8 pages.

56/8=7

7 stickers on each page.

5 0

3 years ago

PLZ ANSWER!!

lesya692 [45]

Answer:Peanut oil freezes at a higher temperature because 3.1°C > -20°C

5 0

3 years ago

Read 2 more answers

Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to

Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

1c) The null hypothesis is not rejected

2a) p-hat=0.64

2b) P=0.0027

2c) The null hypothesis is rejected

3a) p-hat=0.55

3b) P=0.153

3c) The null hypothesis is not rejected

Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.3*0.7}{100}}=0.046$

The sample size is n=100.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.38-0.3}{0.046}=\frac{0.08}{0.046}= 1.74$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02$

The sample size is n=500.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

$\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035$

The sample size is n=200.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

8 0

3 years ago

A wheelchair ramp is in the shape of a triangular prism. it has a base area of 37.4 square yards and a height of 5 yards. find t

mina [271]

It's not the volume of the ramp, it's the angle.

anyways here's how to use trig to find the answer:

Tan <A= opposite/ adjacent
Tan <A= 5.0/ 37.4

<A= tan-1 (5.0/ 37.4)

<A= 7.61 degrees.

7 0

3 years ago