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3 years ago

Determine whether the given equation has one solution, no solution, or infinitely many solutions.

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

No solution

Step-by-step explanation:

Simplify the left side.

− 3 x − 10 =3 ( 3 − x )

Simplify

3 ( 3 − x ).

− 3 x − 10 = 9 − 3 x

Move all terms containing x to the left side of the equation.

− 10 = 9

Since

− 10 ≠ 9 , there are no solutions.

No solution

DochEvi [55]3 years ago

4 0

No solution
Step-by-step explanation:
Simplify the left side.
− 3 x − 10 =3 ( 3 − x )
Simplify
3 ( 3 − x ).
− 3 x − 10 = 9 − 3 x
Move all terms containing x to the left side of the equation.
− 10 = 9
Since
− 10 ≠ 9 , there are no solutions.
No solution

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Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC . What is the leng

Thepotemich [5.8K]

Answer:

Length of side of rhombus is $x=\frac{ab}{a+b}$

Step-by-step explanation:

Given Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC. We have to find the length of side of rhombus.

It is also given that AB=a and AC=b

Let side of rhombus is x.

In ΔCEF and ΔCBA

∠CEF=∠CBA (∵Corresponding angles)

∠CFE=∠CAB (∵Corresponding angles)

By AA similarity rule, ΔCEF~ΔCBA

∴ their sides are in proportion

$\frac{EF}{AB}=\frac{CF}{AC}$

⇒ $\frac{x}{a}=\frac{b-x}{b}$

⇒ $xb=ab-ax$

⇒ $x(a+b)=ab$

⇒ $x=\frac{ab}{a+b}$

Hence, length of side of rhombus is $x=\frac{ab}{a+b}$

6 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$