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3 years ago

Determine whether the given equation has one solution, no solution, or infinitely many solutions.

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

No solution

Step-by-step explanation:

Simplify the left side.

− 3 x − 10 =3 ( 3 − x )

Simplify

3 ( 3 − x ).

− 3 x − 10 = 9 − 3 x

Move all terms containing x to the left side of the equation.

− 10 = 9

Since

− 10 ≠ 9 , there are no solutions.

No solution

DochEvi [55]3 years ago

4 0

No solution
Step-by-step explanation:
Simplify the left side.
− 3 x − 10 =3 ( 3 − x )
Simplify
3 ( 3 − x ).
− 3 x − 10 = 9 − 3 x
Move all terms containing x to the left side of the equation.
− 10 = 9
Since
− 10 ≠ 9 , there are no solutions.
No solution

Read more on Brainly.com - brainly.com/question/14144021#readmore

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Plz help and show how you did the math question

Nikitich [7]

Answer:

$x = - 3$

$y = - 2$

Step-by-step explanation:

Since y=x+1 plug it into bottom equation as y.

$x + 1= 5x + 13$

Subtract 1 from both sides

$x = 5x + 12$

Subtract 5x from both sides

$- 4x = 12$

Divide both sides by -4

$x = - 3$

Now x=-3 into the top equation to find y

$- 3 + 1 = - 2$

y=-2

8 0

3 years ago

Under his cell phone plan, Ian pays a flat cost of $59.50 per month and $5 per gigabyte. He wants to keep his bill under $80 per

inessss [21]

You would start by saying his budget is $80 so you start with 80= he pays an initial fee of $59.50 every month plus $5 per gigabyte so you would set it up like
80=59.50+5x
X being how many gigabytes he uses then you solve 80-59.50 is 20.5 divided by 5 gives you 4.1 but you round down cause you don’t want to pass the limit so therefor the most gigabytes he can use is 4

3 0

3 years ago

On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

3 years ago

Which of the following rational functions is graphed below?

Zepler [3.9K]

Answer:

D. F(x) = 1/(x +5)²

Step-by-step explanation:

The vertical asymptote at x=-5 tells you that x=-5 will be a zero of the denominator. The only equation with a denominator factor of (x+5) is ...

F(x) = 1/(x +5)²

_____

<em>Additional comment</em>

The fact that the value of F(x) does not change sign at the vertical asymptote tells you the denominator factor will be of even degree. That is taken for granted here, as all denominators are squares in the answer choices.

3 0

2 years ago

How many hours is 8:30 to 12:45?

elena55 [62]

Hi there!

8:30 to 12:45 is four hours and 15 minutes. You could easily count this but if you're having trouble you could also use a clock. :P

Hope this helps!

4 0

3 years ago

Read 2 more answers