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BartSMP [9]
4 years ago
13

If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function". C = {(9, 1

) (8, -3) (7, 5) (-5, 3)} A: Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3} B: Domain: {1, -3, 5, 3} Range: {9, 8, 7, -5} not a function
Mathematics
1 answer:
Deffense [45]4 years ago
4 0

Answer:

A: Domain: {9, 8, 7, -5} Range: {1, -3, 5, 3}

Step-by-step explanation:

C = {(9, 1) (8, -3) (7, 5) (-5, 3)}

The domain is the inputs

Domain: { -5,7,8,9}

The range is the output

Range{ -3,1,3,5}

This is a functions since there is no input that goes to multiple outputs

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4 years ago
1. In Kite ABCD below, point E is the midpoint of segment BD. What are the
Anvisha [2.4K]

Answer:

The coordinates of point D( 4,4)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are E(10,4) and B(16,4)

'E' is the mid-point of segment BD

Let D(x₁, y₁) be a point

   E = midpoint of segment BD

 (10,4) = (\frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )

10 = \frac{x_{1} +16 }{2}    

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<u><em>Step(ii):-</em></u>  

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\frac{4 +y_{2} }{2}  =  4

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The co-ordinates of point D( 4,4)

6 0
3 years ago
HELP!<br> Simplify the sum.<br> d^2+4d+3/d^2-7d-8 + d^2-2d-8/d^2+5d+6
nignag [31]
To simplify the expression we proceed as follows:
<span>d^2+4d+3/d^2-7d-8 + d^2-2d-8/d^2+5d+6
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8 0
3 years ago
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ch4aika [34]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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oee [108]

Answer:

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Step-by-step explanation:

I hope this helps:>  If correct feel free to mark brainliest

3 0
3 years ago
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