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JulsSmile [24]
3 years ago
15

Mr. and Mrs. Carlo want to buy a new car, but they do not have enough money in their bank account to pay the entire cost after t

axes and fees. What would be the the most reasonable option for them to get the car?
A. They can become friends with the salesman and get a deal
B. They can get a loan from a bank and make monthly payments.
C. They can sell their house and use the money to pay in full.
D. They can ask to borrow the car until they have enough money.
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0
The answer is B. They get a loan and pay each month, because then they have time to get the money to pay it back while still getting the car.
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Step-by-step explanation:

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3 years ago
3a + 2b, when a = 10 and b= 5
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Answer:

40

Step-by-step explanation:

3a + 2b =

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I hope this helps!

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The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

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To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
2 years ago
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vovangra [49]

Answer:

2(5y+4)

Step-by-step explanation:

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