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3 years ago

PLEASE HELP IM DESPERATE AND WILL VOTE BRAINLIEST

Mathematics

2 answers:

Dahasolnce [82]3 years ago

6 0

Answer:

Step-by-step explanation:

Zina [86]3 years ago

5 0

The answer is 5

i hope this helps luv ❤️❤️❤️ have a great day!

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Please help ASAP (middle school) (Probability )

White raven [17]

Answer: Yes, it is Unlikely.

Step-by-step explanation: All the animals added up equals to 55. Then 2/55 is converted to a percent which is 4% approximately

7 0

3 years ago

Read 2 more answers

In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel

Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

Now,

change in sulfur oxide with time i.e $\frac{\textup{dS}}{\textup{dt}}$

differentiating the given relation with respect to time 't'

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = $2\times110P\frac{\textup{dP}}{\textup{dt}}$ + 20

at P = 100 and $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = 2 × 110 × 100 × 10 + 20

$2S\frac{\textup{dS}}{\textup{dt}}$ = 220020

$\frac{\textup{dS}}{\textup{dt}}$ = $\frac{\textup{220020}}{\textup{2S}}$

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

8 0

2 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

Writer y=3/4x+8 in standard form

Harman [31]

Answer:

3x - 4y = -32

Step-by-step explanation:

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3 years ago

2x −3 y = 21 hmu wit da answer

bazaltina [42]

slope is 2/3 and y intercept is 7

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2 years ago