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Sergio039 [100]
3 years ago
13

PLEASE HELP IM DESPERATE AND WILL VOTE BRAINLIEST

Mathematics
2 answers:
Dahasolnce [82]3 years ago
6 0

Answer:

5

Step-by-step explanation:

Zina [86]3 years ago
5 0
The answer is 5

i hope this helps luv ❤️❤️❤️ have a great day!
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A. What would be the cost of the Standard Daily Rate plus Mileage plan?
Jobisdone [24]

Answer:

Part a) \$190

Part b) \$315

Part c) Standard Daily Rate plus Mileage plan

Step-by-step explanation:

Part a) What would be the cost of the Standard Daily Rate plus Mileage plan?

Let

y ----> the total cost

x ----> the number of kilometers

we have that

For a Luxury car

y=70+0.30x

For x=400 km

substitute

y=70+0.30(400)

y=\$190

Part b) What would be the cost of the Unlimited Mileage plan?

we know that

The Unlimited Mileage plan for a Luxury car is $105 per day (see the table)

The trip are three days

so

To find the total cost multiply $105 by 3

3(\$105)=\$315

Part c) Which is the better plan?

Compare

\$190 < \$315

therefore

For this trip the better plan is the Standard Daily Rate plus Mileage plan

7 0
4 years ago
Mr. Hines was arranging desks into rows for his classroom . Mr. Hines has 20 desks in his class. Draw an array to show how Mr. H
emmainna [20.7K]
There would be four rows of 5. If he added one more row of desks he would have 25 desks. 
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4 0
4 years ago
Read 2 more answers
Here is a table of values for y=f(x).
GenaCL600 [577]

i would pick number C) since i think it would be the correct answer

5 0
3 years ago
I need help PLEASEEEEEEEEEEEEEE
cupoosta [38]

Answer:

318

Step-by-step explanation:

318 is the required answer

I hope it helped you

So given Figure we need to find total surface area

=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)

=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)

From figure,

AB=DC=PQ=SR=9 cm

BQ=CR=AP=DS=11 cm

BC=AD=QR=SP=3 cm

On substituting these values We get

Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)

=27+33+27+33+99+99=318

I hope it helped you

4 0
2 years ago
Read 2 more answers
This is confusing<br> (2x+y)^2−(x−2y)^2
Iteru [2.4K]

Answer:

{(2x + y)}^{2}  -  {(x - 2y)}^{2}

<  {(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2}  >

<  {(x - y)}^{2}  =  {x}^{2}  - 2xy +  {y}^{2}  >

{(2x)}^{2}  + 2(2x)(y) +  {(y)}^{2}  -  {(x)}^{2}  - 2(x)(2y) +  {(2y)}^{2}

{4x}^{2}  + 4xy +  {y}^{2}  -  {x}^{2}  - 4xy +  {4y}^{2}

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= {3x}^{2}  +  {5y}^{2}

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3 years ago
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