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3 years ago

My denomination is 6 more than my numerator my simplest form is 2/5 what fraction am i

Mathematics

1 answer:

gladu [14]3 years ago

3 0

Answer:

4/10

Step-by-step explanation:

4/10 is equal to 2/5, and 4+6=10

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Answer:536 CM

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3 years ago

na organização da festa junina da escola turma do 8º ano e gostou 14 do recurso que tinha com a comida explique 15 com a bebidas

Alex787 [66]

Answer:

1.soso

2.iglo

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3 years ago

HURRRYYY PLEEEASE<br> What is the Slope?<br> (hint: rise/run)<br> No robots please

dexar [7]

-0.5 i believe :)))))))

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3 years ago

VMariaS [17]

Answer

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Step-by-step explanation:

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3 years ago

Item 15 Question 1 Show that quadrilateral WXYZ with vertices W(−1,6), X(2, 8), Y(1, 0), and Z(−2,−2) is a parallelogram by find

Aliun [14]

Answer:

Multiple answers

Step-by-step explanation:

A parallelogram is a flat shape that has four sides. The two sets of opposite sides are parallel and of equal length to each other.

To prove that our figure is a parallelogram we first get the slope of our sides.

The formule we use to get the slope is:

m = $\frac{y-y1}{x-x1}$

first we have the W-Z side that it's supossed to be parallel to X-Y side

if we use our formule to calculate the slope of W-Z:

$\frac{6-(-2)}{-1-(-2)}$ = $\frac{8}{1}$ = 8

if we use our formule to calculate the slope of X-Y:

$\frac{8-0}{2-1}$ = $\frac{8}{1}$ = 8

We know that parallel lines will never intersect because they have the same slope, therefore W-Z side is parallel to X-Y side

2. Then we have the W-X side that it's supossed to be parallel to Z-Y side

if we use our formule to calculate the slope of W-X:

$\frac{6-8}{-1-2}$ = $\frac{-2}{-3}$

if we use our formule to calculate the slope of Z-Y:

$\frac{-2-0}{-2-1}$ = $\frac{-2}{-3}$

We know that parallel lines will never intersect because they have the same slope, therefore W-X side is parallel to Z-Y side

Then we have to prove that the parallalel sides are equal length to each other.

The formule we use to get the distance between two points is:

$\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

We calculate the lenght of the W-Z side that it's supossed to be equal to X-Y side:

W-Z = $\sqrt{(-1-(-2))^{2}+(6-(-2))^{2} }$ = $\sqrt{65}$

X-Y = $\sqrt{(2-1)^{2}+(8-0)^{2} }$ = $\sqrt{65}$

So the W-Z side have the same lenght to X-Y side.

We calculate the lenght of the W-X side that it's supossed to be equal to Z-Y side:

W-X = $\sqrt{(-1-2)^{2}+(6-8)^{2} }$ = $\sqrt{13}$

Z-Y = $\sqrt{(-2-1)^{2}+(-2-0)^{2} }$ = $\sqrt{13}$

So the W-X side have the same lenght to Z-Y side.

6 0

3 years ago