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HACTEHA [7]
3 years ago
11

Darla has written the numbers 1-12 on twelve cards of the same size. she picks two cards at random, without replacing the first

one. Find the probability of drawing cards with numbers that are multiples of 4.
Mathematics
1 answer:
Vikki [24]3 years ago
4 0
25% you are welcome thx me later
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A hotel charges $225 per night to rent a suite. The hotel charges $75 per day for full room service . If Jessica and Ashley purc
Mrrafil [7]
A) 3
the reason is because $225 a night and $75 a day 75*2 is 175 so then you add 175+225 is 400 multiple it by 3 your answer is $1200 enjoy your answer
4 0
3 years ago
One hose can fill a small swimming pool in 65 minutes. A larger hose can fill the pool in 35 minutes. How long will it take the
tatuchka [14]

Answer:

22.75 minutes or 22 minutes 45 seconds

Step-by-step explanation:

Okay, this is a working together question. Let’s walk through it together!

Firstly, let’s say the total volume of the swimming pool is x sq.meters

Now, the rate of the smaller hose would be x/65 while that of the larger will be x/35

Now, their combined rate would be x/65 + x/35 = 100x/2275

Now, since the volume is x, the time taken is simply, the volume divided by the joint rate. That is mathematically equal to x divided by 100x/2275

x * 2275/100x = 2275/100 = 22.75 minutes or 22 minutes 45 seconds

8 0
3 years ago
THis is wierd math g g g g g
Ganezh [65]
It’s 3.5

use formula the formula
V=lwh
——
3

7 0
2 years ago
Clarissa got a part time job during the first week she earned $439.50. During the second and third week she worked a total of 62
iren2701 [21]

Answer:

$2063.44

Step-by-step explanation:

1st week = $439.50

2nd and 3rd week = 62 hours and each hour = $22.79

Total amount earned in 2nd and 3rd week = 62 * 22.79 = $1412.98

4th week = 48% of what she earned in her first week = 48% of $439.50

4th week = (48 / 100) * 439.50 = $210.96

Total amount she earned = 1st week + 2nd & 3rd week + 4th week

Total amount = $439.50 + $1412.98 + $210.96

Total amount = $2063.44

She earned a total of $2063.44

6 0
3 years ago
The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
3 years ago
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