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nasty-shy [4]
3 years ago
6

(8.41 x 10 to the fourth) + (9.71 x 10 to the fourth)

Mathematics
1 answer:
Ivan3 years ago
7 0
The answers are 84100 and 97400
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What is (5.03x -8.03) - (3.5x +6.2)?
Kryger [21]

Answer:

1.53x−14.23

Step-by-step explanation:

<em>simplify: </em>

5.03x−8.03−(3.5x+6.2)

<em>Distribute the Negative Sign:</em>

=5.03x−8.03−1(3.5x+6.2)

=5.03x−8.03−1(3.5x)+(−1)(6.2)

=5.03x−8.03−3.5x−6.2

<em>Combine Like Terms:</em>

=5.03x−8.03+−3.5x−6.2

=(5.03x−3.5x)+(−8.03−6.2)

=1.53x−14.23

4 0
2 years ago
Read 2 more answers
13x^-5 y^0/5^-3 z^-10
VMariaS [17]

Answer:

\frac{1625z^{10}}{x^{5}}

Step-by-step explanation:

We want to simplify:

\frac{13x^{-5}y^0}{5^{-3}z^{-10}}

We rewrite as positive index to get:

\frac{13y^05^{3}z^{10}}{x^{5}}

This simplifies to

\frac{13*1*125z^{10}}{x^{5}}

This will finally give us:

\frac{1625z^{10}}{x^{5}}

We cannot simplify further.

Hence the simplest form is \frac{1625z^{10}}{x^{5}}

7 0
2 years ago
What are 3 number sentences that equals 1?
wolverine [178]

Answer:

.25 X 4 = 1

.50 X 2 = 1

.10 X 10 = 1

Step-by-step explanation:

:)

6 0
2 years ago
Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w
Arte-miy333 [17]
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if x=16 and y=2k+1 are integers, then so are x^2-y^2, 2xy, and x^2+y^2.

However, 4k^2+4k+257 is not a perfect square trinomial, which means for any integer k, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
4 0
3 years ago
Can someone please help me answer these questions? Fill in the blank
agasfer [191]
1. 100
2. 20
3. 2
4. 150
5. 0
6. 21
7. 16
4 0
3 years ago
Read 2 more answers
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