Answer:
60cm²
Step-by-step explanation:
Area of a rectangle = length x breath
Let,
length (L) = (a-1) cm
breadth (B) = (a+3) cm
Putting the value of a = 7;
we get,
length= 7-1 = 6 cm
breadth= 7+3 = 10 cm
Therefore, area of the rectangle = L x B
= 6 x 10
= 60 cm²
Answer:
The system of equations is given as:
x + y = 2.5 .... Equation 1
1.8x + 1.8y = 4.05....Equation 2
Step-by-step explanation:
Kiran says, "I bought 2.5 pounds of red and yellow lentils. Both were $1.80 per pound. I spent a total of $4.05
Let
x represent red lentils
y represent yellow lentils.
x + y = 2.5 .... Equation 1
x = 2.5 - y
$1.80 × x + $1.80 × y = $4.05
1.80x + 1.80y = 4.05....Equation 2
The system of equations is given as:
x + y = 2.5 .... Equation 1
1.8x + 1.8y = 4.05....Equation 2
Answer:
The value of the quantity after 87 months will be of 599.64.
Step-by-step explanation:
A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.
This means that the quantity, after t periods of 6 years, is given by:

What is the value of the quantity after 87 months, to the nearest hundredth?
6 years = 6*12 = 72 months
So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).


The value of the quantity after 87 months will be of 599.64.
Answer:
The surface area is equal to 
Step-by-step explanation:
The surface area of the triangular pyramid is equal to the area of its four triangular faces
so
In this problem
![SA=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have


substitute the values
![SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2815%29%2813%29%5D%3D390%5C%20in%5E%7B2%7D)