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3 years ago

13x^-5 y^0/5^-3 z^-10

Mathematics

1 answer:

VMariaS [17]3 years ago

7 0

Answer:

$\frac{1625z^{10}}{x^{5}}$

Step-by-step explanation:

We want to simplify:

$\frac{13x^{-5}y^0}{5^{-3}z^{-10}}$

We rewrite as positive index to get:

$\frac{13y^05^{3}z^{10}}{x^{5}}$

This simplifies to

$\frac{13*1*125z^{10}}{x^{5}}$

This will finally give us:

$\frac{1625z^{10}}{x^{5}}$

We cannot simplify further.

Hence the simplest form is $\frac{1625z^{10}}{x^{5}}$

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Which of the following is an example of a quadratic equation?

jasenka [17]

Answer:

C) any eqaution that has a variable or number squared is a qaudratic equation

5 0

3 years ago

Use the table for 19-23. write each ratio in the form a/b and then as a decimal. Tell whether each decimal is a terminating or r

stellarik [79]

All you are basically doing is making ratios.
Basketball to football would be 5 to 11 or 5:11 or 5/11.
What you do is in the order you said it (basketball to football) you find that info and make it a ratio. A ratio must be simplified and can be written 3 ways, as shown above.

Hockey to lacrosse would be 6 to 10 and simplified would be 3 to 5.

Try doing 3 and 4 and 5 on your own to help you understand it more:) if you have any questions tell me.

4 0

3 years ago

Read 2 more answers

Y = -3x + 11<br> y = -6x - 13

Marysya12 [62]

Answer:

x= -8 and so y=35.....solving equation

5 0

3 years ago

I DONT KNOW THESE! HELP!

kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

$2y+18=3x-1\\ \\6x-3=17-5y$

Solve this system of two equations:

$\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.$

Multiply the first equation by 2 and add two equations:

$2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2$

Substitute it into the first equation:

$2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5$

21. Opposite angles in the parallelogram are congruent, so

$11x+5=10y+6$

Consecutive angles are supplementary, so

$6x-y+11x+5=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.$

From the second equation

$y=17x-175$

Substitute it into the first equation:

$11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12$

22. Opposite angles in the parallelogram are congruent, so

$2x-5=3y-12$

Consecutive angles are supplementary, so

$2x-5+7y+x=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.$

From the first equation

$x=-3.5+1.5y$

Substitute it into the second equation:

$3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22$

23. Opposite sides in the parallelogram are congruent, so

$2x+9=4y-9\\ \\3x-5=2y+8$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.$

Multiply the second equation by 2 and subtract it from the first equation:

$2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11$

Substitute it into the first equation:

$2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10$

3 0

3 years ago

Can anyone help me figure out how to do this

3241004551 [841]

Answer:

$133m^2$

Step-by-step explanation:

What if i say NO?

3*3=9

8+3=11

12-3=9

9*11=99

2 area coverd so far

99+9=108

7*2=14

108+14=122

Lastly the tir

10-7=3

11-3-2=6

6*4=24

24/2=12

$133m^2$

8 0

3 years ago