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lana [24]
3 years ago
5

Classify the polynomial: 5x^3+8

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0
Cubic binomial. There is one variable of 2 that is raised to the cubic power.
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There are 60 players on a high school football team. The ratio of juniors and seniors to freshmen and sophmores on the team is 2
nata0808 [166]
You know that the ratio of J&S to F&So is 2:3. You need two numbers that have that same ratio to total 60 players.  When you multiply both numbers by 12, you have a ratio of 2:3 but the number of players is 24 to 36.  Thus, the total players is 60.  When looking at the ratio of Juniors to Seniors, the ratio remains 1:2, but must total 24 players.  Dividing the total players by 3, you can find where 1 part of the players equals 2 parts of the others.  Keeping that same ratio in mind, you are able to calculate that the ratio of Juniors to Seniors is 8:16 but when reduced, still remains a 1:2 ratio.
7 0
3 years ago
Read 2 more answers
Ben needs to buy orange juice. He can buy 64 fl oz at the grocery store for $2.00, or he can buy 256 fl oz at the wholesale club
maw [93]
2. unit price = $ ÷ oz 
<span>a) 64 fl oz for $2 = 2/64 ≈ $0.031 per ounce </span>
<span>b) 256 fl oz for $7.5 = 7.5/256 = $0.029 per ounce </span>
<span>c) buy wholesale because 0.029 < 0.031 </span>

<span>3. unit rate means 1 for the miles </span>
<span>3/10 in ÷ 7/8 mi </span>
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8 0
3 years ago
The amount of coffee that a filling machine puts into an 8-ounce jar is normally distributed with a mean of 8.2 ounces and a sta
nordsb [41]

Answer:

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 8.2, \sigma = 0.18, n = 100, s = \frac{0.18}{\sqrt{100}} = 0.018

What is the probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce?

This is the pvalue of Z when X = 8.2 + 0.02 = 8.22 subtracted by the pvalue of Z when X = 8.2 - 0.02 = 8.18. So

X = 8.22

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.22 - 8.2}{0.018}

Z = 1.11

Z = 1.11 has a pvalue of 0.8665

X = 8.18

Z = \frac{X - \mu}{s}

Z = \frac{8.18 - 8.2}{0.018}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

0.8665 - 0.1335 = 0.7330

73.30% probability that the sampling error made in estimating the mean amount of coffee for all 8-ounce jars by the mean of a random sample of 100 jars will be at most 0.02 ounce

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3 years ago
In a certain lottery, 3 balls are drawn (at random) from 10 white balls numbered from 1 to 10, and one special ball is drawn (at
prohojiy [21]

Answer:

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Step-by-step explanation:

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3 years ago
8 for 2 pound of rice in unit rate
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8/2 pound, simplified 4/1 pound
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