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3 years ago

Simplify the following. - (3z)2

Mathematics

2 answers:

Sedaia [141]3 years ago

4 0

Answer:

-6z

Step-by-step explanation:

(3z)2=6z

Add the negative

-6z

vodomira [7]3 years ago

4 0

Answer:

-(3z)2

distribute the -

-3z*2

Step-by-step explanation:

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How to write an expression with distributive property with4+36x

chubhunter [2.5K]

4(9x+1) would be the correct way to write the expression in distributive property.

3 0

4 years ago

Find the arc length of AB. Round your answer to the nearest hundredth.

Fantom [35]

The arc length of AB is 8 m (app.)

Explanation:

Given that the radius of the circle is 8 m.

The central angle is 60°

We need to determine the arc length of AB

The arc length of AB can be determined using the formula,

$arc \ length=\frac{central \ angle}{360^{\circ}} \times circumference$

Substituting central angle = 60° and circumference = 2πr in the above formula, we get,

$arc \ length=\frac{60^{\circ}}{360^{\circ}} \times 2 \pi(8)$

Simplifying the terms, we get,

$arc \ length=\frac{8 \pi }{3}$

Dividing, we get,

$arc \ length=8.37758041$

$arc \ length=8(app.)$

Hence, the arc length is approximately equal to 8.

Therefore, the arc length of AB is 8 m

5 0

4 years ago

The number of internet users in mexico between 2004 and 2008 can be modeled as u(t) = 8.02(1.17t) million users where t is the n

maxonik [38]

Answer:

a) 1.479 Million

b) 36.9%

c) 13.668%

Step-by-step explanation:

The complete question is attached in the image below.

The number of internet users in Mexico between 2004 and 2008 is modelled by the following equation:

$u(t)=8.02(1.17)^{t}$

Where, u(t) is in millions and t is the number of years since 2004.

Part a) Rate of change of internet users between 2004 and 2006

The rate of change of a function is defined as:

$\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$

We have to find the rate of change between 2004 and 2006. For 2004 t = 0, and for 2006, t = 2. So the rate of change for the given function will be:

$\frac{u(2)-u(0)}{2-0}\\\\ =\frac{8.02(1.17)^{2}-8.02(1.17)^{0}}{2}\\\\ =1.479$

Thus, the average rate of change in number of internet users in Mexico from between 2004 and 2006 was 1.479 million.

Part b) Percentage change of internet users between 2004 and 2006

The formula to calculate the percentage change is:

$\frac{\text{New value - Original Value}}{\text{Original Value}} \times 100\%$

Here, New value means the users in 2006 and original value means the users in 2004.

Using the values in this formula, we get:

$\frac{8.02(1.17)^{2}-8.02(1.17)^0}{8.02(1.17)^{0}} \times 100\%\\\\ =36.89\%$

Thus, the percentage change in the number of internet users between 2004 and 2006 was 36.89%

Part c) Percentage of internet users in 2008

For 2008, t would be equal to 4.

So, the number of internet users in Mexico in 2008 would be = $8.02(1.17)^{4}=15.02857542$ million = 15,028,575 (rounded to nearest integer)

Total population of Mexico in 2008 = 109,955,400

We have to calculate what percentage of Mexico population was Internet users in 2008. The formula for this would be:

$\frac{\text{Concerned Value}}{\text{Total Value}} \times 100\%$

Here, concerned value is the number of internet users and total value is the total population. Using the values in this formula we get:

$\frac{15028575}{109955400} \times 100\%\\\\=13.668\%$

Thus, 13.668% of the population was internet users in 2008 in Mexico.

5 0

3 years ago

On average, Ryan can finish a puzzle in 3 hours but, depending on the difficulty of the puzzle, his time can vary from the avera

Nuetrik [128]

Answer:

|x − 3| = 2

Step-by-step explanation:

The difference between his maximum time and his average time is +2 hours.

x − 3 = 2

The difference between his minimum time and his average time is -2 hours.

x − 3 = -2

Using absolute values:

|x − 3| = 2

5 0

3 years ago

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Kim bought 2 pounds of green apples and 3.2 pounds of yellow apples from the market. Both apples were $1.65 per pound. How much

Lesechka [4]

Answer:

8.3325

Step-by-step explanation:

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4 years ago