Answer:
Triangle BCA and Triangle KIJ are congruent by SAS rule
These are correct statements:
<span>- Line segments AB and CD are parallel.
- </span>Since ∠1 and ∠3 are corresponding angles, they are congruent.
These are incorrect statements:
- <span>Since ∠3 and ∠4 are corresponding angles, they are congruent. They are not corresponding angles, they are supplementary meaning they, together, equal 180.
- </span><span>Since ∠1 and ∠2 are corresponding angles, they are congruent. These are also not corresponding, they are supplementary.
- </span><span>Line segments AB and CD are perpendicular. They are not crossing over each other.</span>
- <span>Since ∠1 and ∠4 are alternate interior angles, they are congruent. They are not corresponding, they are supplementary. </span><span>∠1 and </span><span>∠3 are corresponding just like </span>∠2 and <span>∠4. </span>
Answer:
195 answer.plus minus plus minus plus minus
Answer: 89
43 + x = 132 => Exterior Angle Theorem
^
The measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles. That means the two remote interior angle add up to the exterior angle.
x = 89
**To find the last angle: 89 + 43 + x = 180 => Triangle Sum Theorem states that the interior angles of a triangle add up to 180. The last angle would be 48.**
Answer:
= 4·
Step-by-step explanation:
From the midpoint theorem, which states that the line that a line drawn such that it joins the midpoints of two sides of a triangle, is parallel to the third side of the triangle and is equal to half the length of the third side
Therefore, the lengths of the sides of ΔDEF, drawn by joining the midpoints of ΔABC is equal to half the length of and parallel to the corresponding side of ΔABC
We therefore, have that the corresponding sides of ΔABC and ΔDEF have a common ratio and a pair of sides in each triangle form same angles, therefore;
ΔDEF is similar to ΔABC by Side, Side, Side SSS similarity.
The length of the perimeter of ΔABC,
= 2 × The length of the perimeter of triangle ΔEDC, 
= 2 × 
∴
≠ 4 × 
The statement which is incorrect is therefore;
= 4 ×
.