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3 years ago

56 is 4% of how many days

Mathematics

1 answer:

mojhsa [17]3 years ago

8 0

Change the percent to decimal

4%= .04

.04x = 56

solve for x

so x = 1400

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What is the solution to f(x) = g(x)

Vaselesa [24]

Answer:

B) -1 and D) 1

Step-by-step explanation:

We want to find the solution to

$f(x)=g(x)$

Which means that we want to find the values of x at which the two functions f(x) and g(x) are equal.

In order to do that, we have to look at the table, and see at which values of x the two functions have the same value.

We observe that the only two values at which this occurs are:

at $x=-1$ , where both functions are equal to $f(x)=g(x)=-3$

at $x=1$ , where both functions are equal to $f(x)=g(x)=5$

7 0

3 years ago

Solve for b. 63 = 9b+ 54

tiny-mole [99]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

HELP PLEASE ASAP

Pie

$\bold{\huge{\underline{ Solution }}}$

We have, 

Line segment AB
The coordinates of the midpoint of line segment AB is ( -8 , 8 )
Coordinates of one of the end point of the line segment is (-2,20)

Let the coordinates of the end point of the line segment AB be ( x1 , y1 ) and (x2 , y2)

Also, 

Let the coordinates of midpoint of the line segment AB be ( x, y)

We know that,

For finding the midpoints of line segment we use formula :-

$\bold{\purple{ M( x, y) = }}{\bold{\purple{\dfrac{(x1 +x2)}{2}}}}{\bold{\purple{,}}}{\bold{\purple{\dfrac{(y1 + y2)}{2}}}}$

According to the question,

The coordinates of midpoint and one of the end point of line segment AB are ( -8,8) and (-2,-20) .

For x coordinates :-

$\sf{ -8 = }{\sf{\dfrac{(- 2 +x2)}{2}}}$

$\sf{2}{\sf{\times{ -8 = - 2 + x2 }}}$

$\sf{ - 16 = - 2 + x2 }$

$\sf{ x2 = -16 + 2 }$

$\bold{ x2 = -14 }$

For y coordinates :-

$\sf{ 8 = }{\sf{\dfrac{(- 20 +x2)}{2}}}$

$\sf{2}{\sf{\times{ 8 = - 20 + x2 }}}$

$\sf{ 16 = - 20 + x2 }$

$\sf{ y2 = 16 + 20 }$

$\bold{ y2 = 36 }$

Thus, The coordinates of another end points of line segment AB is ( -14 , 36)

Hence, Option A is correct answer

7 0

2 years ago

Find all vertical and horizontal asymptotes of the graph of the function. (Enter your answers as a comma-separated list.)

Vladimir79 [104]

Hello,

y=(1+x)/(1-x)

y=-1
Asymptote horizontal $\lim_{n \to \infty} \frac{1+x}{1-x} =-1$

x=1
Asymptote vertical $\lim_{x \to 1} \frac{1+x}{1-x}=\infty$

3 0

3 years ago

What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

Find the equation of the circle

The equation of the circle in center radius form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

we have

(h,k)=(3,2)

$r=2\sqrt{41}/2=\sqrt{41}\ units$ ---> the radius is half the diameter

substitute

$(x-3)^{2} +(y-2)^{2}=(\sqrt{41})^{2}$

$(x-3)^{2} +(y-2)^{2}=41$

4 0

3 years ago