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kondor19780726 [428]

2 years ago

9

Jada list these fractions that are all equivalent to 1/2:2/4,3/6,4/8,5/10 she notices that each time the numerator increases by

1 and the denominator increases by 2. Will the pattern jada notices continue? Explain your reasoning.

1 answer:

r-ruslan [8.4K]2 years ago

8 0

yes the pattern Jada sees will continue.

Step-by-step explanation:

Im not sure how to explain it but I hope this helps!

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F(x)=3 over x+2-x-3 squared what is f(7)

dimaraw [331]

<u>Answer:</u>

$f(7)=\frac{-5}{3}$ or $f(7)=-1.67$

<u>Step-by-step explanation:</u>

We are given the following function of x and we are to find the value of $f ( 7 )$ :

$f ( x ) = \frac { 3 } { x + 2 } - \sqrt { x - 3 }$

Substituting the given value (7) in the above function to get:

$f(x)=\frac{3}{x+2}-\sqrt{x-3}$

$f ( 7 )= \ frac{3}{7+2}-\sqrt{7-3}$

$f(7) = \frac { 3 } { 9 } - \sqrt { 4 }$

$f(7)=\frac{1}{3}-2$

$f(7)=\frac{1}{3}-\frac{6}{3}$

$f(7)=\frac{-5}{3}$ or $f(7)=-1.67$

7 0

3 years ago

Can anyone help me with this?

Neko [114]

Answer:

the answer would be 5

Step-by-step explanation:

because if there was 15 truth or false questions that would be 45 points and if there where 5 essay questions that would be 55 questions 45+55=100 points and 15+5 questions is 20 questions so there would be 5 essay questions.

3 0

2 years ago

Graph the linear equation by the point plotting method or by finding intercepts -2y + 10 = 0

Nadusha1986 [10]

Answer:

Your answer is

Intercept is = 5

(x,y)= (0,5)

Hope that this is helpful. Tap the crown button, Like & Follow me

5 0

3 years ago

The polynomial function y = x3 -3x2 + 16x - 48 has only one non-repeated x-intercept. What do you know about the complex zeros o

earnstyle [38]

• First way to solve:
We'll manipulate the expression of the equation:

$y=x^3-3x^2+16x-48\\\\ y=x^2(x-3)+16(x-3)\\\\ y=(x-3)(x^2+16)$

If we have y=0:

$x-3=0~~~or~~~x^2+16=0\\\\ x=3~~~or~~~x^2=-16\\\\ x=3~~~or~~~x=\pm\sqrt{-16}\\\\ x=3~~~or~~~x=\pm4i$

Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

Answer: B

• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

Answer: B.

3 0

3 years ago

The sooner the better

slega [8]

the answer is A

do I have to explain?

3 0

3 years ago

Read 2 more answers