Answer:
75.02 ft
Step-by-step explanation:
Split the problem into 2 different part. The bottom part of the tree is 5 feet because that's where your eye levels are, so you just have to solve the top part of the tree.
The top part of the tree is solved by finding the height of the triangle. If you remember SohCahToa, the opposite side of the angle is solved using tangent.
tan(angle) = opposite/adjacent
tan(35) = x/100, x is just the unknown height of the tree.
multiply 100 on both side to get x by itself.
x = 100tan(35)
x = 70.02
add that top height of the tree(70.02ft) with the bottom height of the tree(5ft).
70.02+5 = 75.02 ft
The answer is 112 you have to add each of the sides up. There are 4 triangles 6x4 is 24 so 24x4 because there are 4 triangles and there is 1 square and if all of the sides are the same then it is 4x4 which is 16. Then you have 112 because, 24 x4 is 96 pulse 16 is 112
Tan42°=x/35
x=35tan42° units
x≈31.51 units (to nearest hundredth of a unit)
Answer:
The bird will be at a ground distance of 10.04 units away.
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:
It's vertex is the point 
In which
Where
If a<0, the vertex is a maximum point, that is, the maximum value happens at 
, and it's value is 
.
Equation for the height:
The height of the bird after x seconds is given by:
Which is a quadratic equation with 
.
When the bird is at its highest?
Quadratic equation with 
, and thus, at the vertex. The ground distance is the x-value of the vertex. Thus
The bird will be at a ground distance of 10.04 units away.
